ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÂÈ»¯·¨ÊǺϳÉÁòõ£ÂÈ£¨SO2Cl2£©µÄ³£Ó÷½·¨£¬ÊµÑéÊҺϳÉÁòõ£ÂÈ£¨SO2Cl2£©µÄ·´Ó¦ºÍʵÑé×°ÖÃÈçÏ£º
SO2(g)£«Cl2(g) SO2Cl2(l) ¦¤H£½- 92.7 kJ/mol
ÓйØÐÅÏ¢ÈçÏ£ºÁòõ£ÂÈͨ³£Ìõ¼þÏÂΪÎÞÉ«ÒºÌ壬ÈÛµãΪ£54.1 ¡æ£¬·ÐµãΪ69.1 ¡æ£¬ÃܶÈΪ1.67g /cm3£¬ÔÚ³±Êª¿ÕÆøÖС°·¢ÑÌ¡±£»100¡æÒÔÉÏ¿ªÊ¼·Ö½â£¬Éú³É¶þÑõ»¯ÁòºÍÂÈÆø£¬³¤ÆÚ·ÅÖÃÒ²»á·¢Éú·Ö½â¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©×°Öü×ÖÐÒÇÆ÷AµÄÃû³ÆΪ___________£¬¼×ÖлîÐÔÌ¿µÄ×÷ÓÃÊÇ________£¬BµÄ×÷ÓÃΪ_________£»
£¨2£©×°Öö¡Öз¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ__________________________£»
£¨3£©×°ÖñûÖеÄÊÔ¼ÁΪ____________________£¬ÈôȱÉÙ×°ÖÃÒÒ£¬ÂÈÆøºÍ¶þÑõ»¯Áò¿ÉÄÜ·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ_______________________________________£»
£¨4£©ÎªÌá¸ß±¾ÊµÑéÖÐÁòõ£ÂȵIJúÂÊ£¬ÔÚʵÑé²Ù×÷ÖÐÐèҪעÒâµÄÊÂÏîÓÐ_______£¨ÌîÐòºÅ£©¡£
¢ÙÏÈͨÀäÄýË®£¬ÔÙͨÆø ¢Ú¿ØÖÆÆøÁ÷ËÙÂÊ£¬ÒËÂý²»ÒË¿ì
¢ÛÈôÈý¾±ÉÕÆ¿·¢ÌÌ£¬¿ÉÊʵ±½µÎ ¢Ü¼ÓÈÈÈý¾±ÉÕÆ¿
£¨5£©±¾ÊµÑéÖÐͨÈëSO2µÄÌå»ýΪ11.2 L£¨ÒÑÕÛËã³É±ê×¼×´¿ö£©£¬Cl2³ä×㣬ʵÑé×îÖÕÊÕ¼¯µ½Áòõ£ÂÈ27.0 mL£¬ÔòÁòõ£ÂȵIJúÂÊΪ_________________£¨½á¹û±£ÁôһλСÊý£©¡£
¡¾´ð°¸¡¿ÀäÄý¹Ü£¨ÉßÐÎÀäÄý¹Ü»ò»·ÐÎÀäÄý¹Ü£© ´ß»¯¼Á ·ÀֹˮÕôÆø½øÈ룬ÎüÊÕβÆø Cl+ClO+2H+£½Cl2¡ü+H2O ±¥ºÍʳÑÎË®£¨»ò±¥ºÍÂÈ»¯ÄÆÈÜÒº£© SO2+Cl2+2H2O£½H2SO4+2HCl ¢Ù¢Ú¢Û 66.8%
¡¾½âÎö¡¿
£¨1£©¸ù¾ÝÒÇÆ÷Ìص㣬װÖü×ÖÐÒÇÆ÷AµÄÃû³ÆΪÉßÐÎÀäÄý¹Ü»ò»·ÐÎÀäÄý¹Ü£»»îÐÔÌ¿²»ÊÇ·´Ó¦ÎÔò×÷´ß»¯¼Á£»BÖеļîʯ»Ò¿É·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆø½øÈë×°Ö㬻¹¿ÉÒÔ·ÀÖ¹Óж¾ÆøÌå½øÈë¿ÕÆø£¬½øÐÐβÆø´¦Àí£»
£¨2£©×°Öö¡ÖÐÀûÓÃƯ°×·ÛÓëÑÎËá·´Ó¦ÖÆÈ¡ÂÈÆø£»
£¨3£©×°ÖñûΪ³ýÈ¥ÂÈÆøÖеÄHClÆøÌ壻װÖÃÒÒµÄÊÔ¼ÁΪŨÁòËᣬ¿É·ÀֹˮÕôÆø½øÈë×°Öü×ÖУ¬µ¼ÖÂSO2Cl2ÔÚ³±Êª¿ÕÆøÖС°·¢ÑÌ¡±£»
£¨4£©¢ÙÏÈͨÀäÄýË®£¬ÔÙͨÆø£¬¿É¼õÉÙSO2Cl2µÄ»Ó·¢£»
¢Ú¿ØÖÆÆøÁ÷ËÙÂÊ£¬ÒËÂý²»Ò˿죬¿Éʹ·´Ó¦³ä·Ö½øÐУ»
¢Û100¡æÒÔÉÏSO2Cl2¿ªÊ¼·Ö½â£¬Éú³É¶þÑõ»¯ÁòºÍÂÈÆø£¬ÈôÈý¾±ÉÕÆ¿·¢ÌÌ£¬¿ÉÊʵ±½µÎ£¬¿É¼õÉÙSO2Cl2µÄ·Ö½â£»
¢Ü¼ÓÈÈÈý¾±ÉÕÆ¿£¬·Ö½âÂÊÔö´ó£¬²úÂʽµµÍ£»
£¨5£©¸ù¾Ýn(SO2):n(SO2Cl2)=1£º1£¬×ª»¯ÂÊ=¡Á100%½øÐмÆËã¡£
£¨1£©¸ù¾ÝÒÇÆ÷Ìص㣬װÖü×ÖÐÒÇÆ÷AµÄÃû³ÆΪÉßÐÎÀäÄý¹Ü»ò»·ÐÎÀäÄý¹Ü£»»îÐÔÌ¿²»ÊÇ·´Ó¦ÎÔò×÷´ß»¯¼Á£»BÖеļîʯ»Ò¿É·ÀÖ¹¿ÕÆøÖеÄË®ÕôÆø½øÈë×°Ö㬻¹¿ÉÒÔ·ÀÖ¹Óж¾ÆøÌå½øÈë¿ÕÆø£¬½øÐÐβÆø´¦Àí£»
£¨2£©×°Öö¡ÖÐÀûÓÃƯ°×·ÛÓëÑÎËá·´Ó¦ÖÆÈ¡ÂÈÆø£¬·´Ó¦µÄÀë×Ó·½³ÌʽΪCl+ClO+2H+£½Cl2¡ü+H2O£»
£¨3£©×°ÖñûΪ³ýÈ¥ÂÈÆøÖеÄHClÆøÌ壬ʹÓõÄÊÔ¼ÁΪ±¥ºÍʳÑÎË®£»×°ÖÃÒÒµÄÊÔ¼ÁΪŨÁòËᣬ¿É·ÀֹˮÕôÆø½øÈë×°Öü×ÖУ¬µ¼ÖÂSO2Cl2ÔÚ³±Êª¿ÕÆøÖС°·¢ÑÌ¡±£¬·´Ó¦µÄ·½³ÌʽΪSO2+Cl2+2H2O£½H2SO4+2HCl£»
£¨4£©¢ÙÏÈͨÀäÄýË®£¬ÔÙͨÆø£¬¿É¼õÉÙSO2Cl2µÄ»Ó·¢£¬´Ó¶øÌá¸ß²úÂÊ£¬·ûºÏÌâÒ⣬¢ÙÕýÈ·£»
¢Ú¿ØÖÆÆøÁ÷ËÙÂÊ£¬ÒËÂý²»Ò˿죬¿Éʹ·´Ó¦³ä·Ö½øÐУ¬´Ó¶øÌá¸ß²úÂÊ£¬·ûºÏÌâÒ⣬¢ÚÕýÈ·£»
¢Û100¡æÒÔÉÏSO2Cl2¿ªÊ¼·Ö½â£¬Éú³É¶þÑõ»¯ÁòºÍÂÈÆø£¬ÈôÈý¾±ÉÕÆ¿·¢ÌÌ£¬¿ÉÊʵ±½µÎ£¬¿É¼õÉÙSO2Cl2µÄ·Ö½â£¬´Ó¶øÌá¸ß²úÂÊ£¬·ûºÏÌâÒ⣬¢ÛÕýÈ·£»
¢Ü¼ÓÈÈÈý¾±ÉÕÆ¿£¬·Ö½âÂÊÔö´ó£¬²úÂʽµµÍ£¬ÓëÌâÒâ²»·û£¬¢Ü´íÎó£»
´ð°¸Îª¢Ù¢Ú¢Û£»
£¨5£©¸ù¾Ý·½³ÌʽSO2(g)£«Cl2(g) SO2Cl2(l)£¬n(SO2):n(SO2Cl2)=1£º1£¬m(SO2Cl2)=1.67g /cm3¡Á27.0 mL=45.09g£¬n(SO2Cl2)==0.334mol£¬Ôò·´Ó¦µÄn(SO2) =0.334mol£¬×ª»¯ÂÊ=¡Á100%=66.8%¡£
¡¾ÌâÄ¿¡¿Ì¼×å¡¢µª×åÔªËؼ°Æ仯ºÏÎïÔÚÉú²ú¡¢Éú»îºÍ»·¾³±£»¤ÖÐÓ¦Óù㷺¡£
£¨1£©ÏÂÁÐÓйØÎïÖÊÐÔÖʵݱäµÄÃèÊöÖУ¬ÕýÈ·µÄÊÇ________________£¨Ìî´úºÅ£©¡£
A£®ËáÐÔ£ºHNO3>H2CO3>H2SiO3 B£®Îȶ¨ÐÔ£ºNH3>AsH3>PH3
C£®Îȶ¨ÐÔ£ºN2<P4£¨°×Á×£© D£®³£ÎÂÏ£¬Í¬Å¨¶ÈÈÜÒºµÄpH£ºNa3PO4<Na3AsO4
£¨2£©ÒÑÖª£º
(a)CH4(g)+2O2(g)=CO2(g)+2H2O(l) ¦¤H1=£890.3 kJ¡¤mol1
(b)2H2(g)+O2(g)=2H2O(l) ¦¤H2=£571.6 kJ¡¤mol1
(c)C(s)+O2(g)=CO2(g) ¦¤H3=£393.5 kJ¡¤mol1
¢ÙC(s)+2H2(g)=CH4(g) ¦¤H=___________kJ¡¤mol1¡£
¢ÚCH4ÖƱ¸ºÏ³ÉÆøµÄÔÀíÊÇCH4(g)+CO2(g) 2CO(g)+2H2(g)¡£
A. ÏÂÁÐÐðÊö²»Äܱíʾ¸Ã·´Ó¦ÔÚºãκãÈÝÌõ¼þÏ´ﵽƽºâ״̬µÄÊÇ____¡£
a. »ìºÏÆøÌåµÄѹǿ²»ÔÙ·¢Éú±ä»¯
b. »ìºÏÆøÌåµÄÃܶȲ»ÔÙ·¢Éú±ä»¯
c. ·´Ó¦ÈÝÆ÷ÖÐCO2¡¢COµÄÎïÖʵÄÁ¿µÄ±ÈÖµ²»ÔÙ·¢Éú±ä»¯
d. »ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿²»ÔÙ·¢Éú±ä»¯
B. Èô1 g CH4(g)ÍêÈ«·´Ó¦ÎüÊÕÈÈÁ¿Îª15.5 kJ¡£ÔÚºãÈÝÃܱÕÈÝÆ÷ÖгäÈë1 mol CH4ºÍ1 mol CO2ÔÚÒ»¶¨Ìõ¼þÏ·´Ó¦£¬ÌåϵÎüÊÕÈÈÁ¿Ëæ×Åʱ¼ä±ä»¯ÈçͼËùʾ¡£ÔÚ¸ÃÌõ¼þÏ£¬¼×ÍéµÄ×î´óת»¯ÂÊ£¨¦Á£©Îª____________¡£
£¨3£©ÔÚÃܱÕÈÝÆ÷Öз¢Éú·´Ó¦£º2NO(g)+H2(g)= N2(g)+2H2O(g)£¬Æä·´Ó¦ËÙÂÊÓëŨ¶È¹ØϵʽΪv=kcm(NO)¡¤cn(H2)£¨kΪ³£Êý£¬Ö»ÓëζÈÓйأ¬m¡¢nΪ·´Ó¦¼¶Êý£¬È¡ÕýÕûÊý£©£¬ÔÚijζÈϲâµÃÓйØÊý¾ÝÈç±íËùʾ¡£
ÐòÊý | c(NO)/(mol¡¤L1) | c(H2)/(mol¡¤L1) | v/(mol¡¤L1¡¤min1) |
¢ñ | 0.10 | 0.10 | 0.414 |
¢ò | 0.20 | 0.20 | 3.312 |
¢ó | 0.10 | 0.20 | 0.828 |
×Ü·´Ó¦·ÖÁ½²½½øÐУºµÚi²½£¬2NO+H2=N2+H2O2(ºÜÂý)£»µÚii²½£¬H2O2+H22H2O£¨ºÜ¿ì£©¡£ÔÚÉÏÊöζÈÏ£¬µ±c(NO)=c(H2)=0.50 mol¡¤L1ʱv=_________mol¡¤L1¡¤min1¡£
£¨4£©ÔÚ2 LºãÈÝÃܱÕÈÝÆ÷ÖгäÈë3 mol NO(g)ºÍ3 mol CO(g)£¬·¢Éú·´Ó¦£º2NO(g)+2CO(g) N2(g)+2CO2(g)£¬ÔÚÒ»¶¨Î¶ÈÏ´ﵽƽºâ£¬²âµÃƽºâÌåϵÖÐc(N2)=0.5 mol¡¤L1¡£Ôò¸ÃÌõ¼þÏÂƽºâ³£ÊýKֵΪ_______¡£·´Ó¦Ç°ºóÈÝÆ÷ÄÚÆøÌåѹǿ֮±ÈΪ_________________________¡£