ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿2 LÃܱÕÈÝÆ÷ÖнøÐз´Ó¦£ºpZ(g)£«qQ(g) mX(g)£«nY(g)£¬Ê½ÖÐm¡¢n¡¢p¡¢qΪ»¯Ñ§¼ÆÁ¿Êý¡£ÔÚ0¡«3 minÄÚ£¬¸÷ÎïÖʵÄÎïÖʵÄÁ¿µÄ±ä»¯ÈçϱíËùʾ£º

ÎïÖÊ

X

Y

Z

Q

Æðʼ/mol

0.7

1

2 minĩ/mol

0.8

2.7

0.8

2.7

3 minĩ/mol

0.8

ÒÑÖª£º2 minÄÚv(Q)£½0.075 mol¡¤L£­1¡¤min£­1£¬v(Z)¡Ãv(Y)£½1¡Ã2¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)2 minÄÚXµÄ·´Ó¦ËÙÂÊv(X)£½__________¡£

(2)Æðʼʱn(Y)£½__________¡£

(3) 3 minÄ©ÊÇ·ñ´ïµ½Æ½ºâ_______(ÌîÊÇ»ò·ñ)¡£

(4)¶ÔÓڸ÷´Ó¦£¬ÄÜÔö´óÕý·´Ó¦ËÙÂʵĴëÊ©ÊÇ________(ÌîÐòºÅ£¬ÏÂͬ)¡£

A£®ËõСÈÝÆ÷Ìå»ý B£®ÒÆ×ß²¿·ÖQ

C£®Í¨Èë´óÁ¿HeÆø D£®Éý¸ßζÈ

¡¾´ð°¸¡¿0.025 mol¡¤L£­1¡¤min£­1 2.3 mol ÊÇ A D

¡¾½âÎö¡¿

¸ù¾Ýͼ±íÊý¾Ý¼°·´Ó¦·½³Ìʽ¼ÆËã·´Ó¦ËÙÂÊ£»¸ù¾ÝÊý¾Ý·ÖÎö·´Ó¦ÊÇ·ñ´ïµ½Æ½ºâ¡£

2 LÃܱÕÈÝÆ÷ÖнøÐз´Ó¦£ºpZ(g)£«qQ(g) mX(g)£«nY(g)£¬Ê½ÖÐm¡¢n¡¢p¡¢qΪ»¯Ñ§¼ÆÁ¿Êý¡£ÔÚ0¡«3 minÄÚ£¬¸÷ÎïÖʵÄÎïÖʵÄÁ¿µÄ±ä»¯ÈçϱíËùʾ£º

ÎïÖÊ

X

Y

Z

Q

Æðʼ/mol

0.7

1

2 minĩ/mol

0.8

2.7

0.8

2.7

3 minĩ/mol

0.8

ÒÑÖª£º2 minÄÚv(Q)£½0.075 mol¡¤L£­1¡¤min£­1£¬v(Z)¡Ãv(Y)£½1¡Ã2¡£

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

(1)2 minÄÚXµÄŨ¶È0.35 mol¡¤L£­1±äΪ0.40 mol¡¤L£­1£¬ËùÒÔv(X)£½=0.025 mol¡¤L£­1¡¤min£­1£¬

¹Ê´ð°¸Îª£º0.025 mol¡¤L£­1¡¤min£­1£»

(2)v(Z)¡Ãv(Y)£½1¡Ã2£¬Ôòp£ºn=1¡Ã2£¬2minÄÚZ·´Ó¦µô1mol-0.8mol=0.2mol£¬ÔòͬʱÉú³ÉYΪ0.2mol¡Á2=0.4mol£¬ÔòÆðʼʱn(Y)£½2.7mol-0.4mol=2.3 mol £¬

¹Ê´ð°¸Îª£º2.3 mol £»

(3) 2minÄ©ºÍ3 minÄ©ZµÄÎïÖʵÄÁ¿ÏàµÈ£¬Ôò˵Ã÷ÒѾ­´ïµ½Æ½ºâ£¬

¹Ê´ð°¸Îª£ºÊÇ£»

(4)A£®ËõСÈÝÆ÷Ìå»ý£¬·´Ó¦ÎïŨ¶ÈÔö´ó£¬Õý·´Ó¦ËÙÂʼӿ죬¹ÊAÕýÈ·£»

B£®ÒÆ×ß²¿·ÖQ£¬·´Ó¦ÎïŨ¶È¼õС£¬Õý·´Ó¦ËÙÂʼõС£¬¹ÊB´íÎó£»

C£®Í¨Èë´óÁ¿HeÆø£¬·´Ó¦ÎïŨ¶È²»±ä£¬Õý·´Ó¦ËÙÂʲ»±ä£¬¹ÊC´íÎó£»

D£®Éý¸ßζȣ¬Õý·´Ó¦ËÙÂʼӿ죬¹ÊDÕýÈ·£¬

¹Ê´ð°¸Îª£ºAD¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿¿ª·¢ÐÂÐÍ´¢Çâ²ÄÁÏÊÇÇâÄÜÔ´ÀûÓõÄÖØÒªÑо¿·½ÏòÖ®Ò»¡£Çë»Ø´ðÒÔÏÂÎÊÌ⣺

(1)Ti(BH4)3ÊÇÒ»ÖÖ´¢Çâ²ÄÁÏ£¬¿ÉÓÉTiCl4ºÍLiBH4·´Ó¦ÖƵá£

¢Ù»ù̬Ti3+µÄµç×ÓÅŲ¼Ê½Îª____________________£»LiBH4ÖÐLi¡¢B¡¢HÔªËصĵ縺ÐÔÓÉ´óµ½Ð¡µÄÅÅÁÐ˳ÐòΪ_________________¡£

¢ÚÁíÓÐÒ»ÖÖº¬îÑÔªËصÄÐÂÐͲÄÁÏ£¬ÆäÀíÂ۽ṹģÐÍÈçͼËùʾ£¬Í¼ÖÐÐéÏß¿òÄÚ̼ԭ×ÓµÄÔÓ»¯¹ìµÀÀàÐÍΪ____________¡£

(2)°±ÅðÍé(NH3BH3)ÊÇÓÅÁ¼µÄ´¢Çâ²ÄÁÏ£¬ÉÙÁ¿°±ÅðÍé¿ÉÒÔÓÉÅðÍé(B2H6)ºÍNH3ºÏ³É¡£

¢ÙNH3BH3ÖÐÊÇ·ñ´æÔÚÅäλ¼ü__________(Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)£»ÓëNH3BH3»¥ÎªµÈµç×ÓÌåµÄ·Ö×ӵĻ¯Ñ§Ê½Îª__________¡£

¢ÚB¡¢C¡¢NÓëOÔªËصĵÚÒ»µçÀëÄÜÓÉ´óµ½Ð¡µÄ˳ÐòΪ___________________¡£

¢Û°±ÅðÍéÔÚ¸ßÎÂÏÂÊÍ·ÅÇâºóÉú³ÉµÄÁ¢·½µª»¯Åð¾§Ì壬¾ßÓÐÀàËƽð¸ÕʯµÄ½á¹¹£¬Ó²¶ÈÂÔСÓÚ½ð¸Õʯ¡£ÔòÁ¢·½µª»¯Åð¾§Ìå¿ÉÓÃ×÷___________(Ñ¡ÌîÏÂÁÐ×ÖĸÐòºÅ)¡£

a£®ÇÐÏ÷¹¤¾ß b£®×ê̽×êÍ· c£®µ¼µç²ÄÁÏ d£®ÄÍÄ¥²ÄÁÏ

(3)Ò»ÖÖÓд¢Ç⹦ÄܵÄÍ­ºÏ½ð¾§Ìå¾ßÓÐÃæÐÄÁ¢·½×îÃܶѻýµÄ½á¹¹£¬¾§°ûÖÐCuÔ­×Ó´¦ÓÚÃæÐÄ£¬AuÔ­×Ó´¦ÓÚ¶¥µãλÖÃ,ÇâÔ­×ӿɽøÈëµ½ÓÉCuÔ­×ÓÓëAuÔ­×Ó¹¹³ÉµÄËÄÃæÌå¿Õ϶ÖС£

¢ÙÈô½«CuÔ­×ÓÓëAuÔ­×ÓµÈͬ¿´´ý£¬¸Ã¾§Ìå´¢ÇâºóµÄ¾§°û½á¹¹ÓëCaF2µÄ½á¹¹ÏàËÆ£¬¸Ã¾§Ìå´¢ÇâºóµÄ»¯Ñ§Ê½Îª________________£»

¢ÚÍ­ÓëÆäËüÐí¶à½ðÊô¼°Æ仯ºÏÎﶼ¿ÉÒÔ·¢ÉúÑæÉ«·´Ó¦£¬ÆäÔ­ÒòÊÇ_______________¡£

(4)½ðÊôÇ⻯ÎïÒ²ÊǾßÓÐÁ¼ºÃ·¢Õ¹Ç°¾°µÄ´¢Çâ²ÄÁÏ¡£Ä³´¢Çâ²ÄÁÏÊǶÌÖÜÆÚ½ðÊôÔªËØRµÄÇ⻯Îï¡£RµÄ²¿·ÖµçÀëÄÜÈçϱíËùʾ£º

I1/KJ¡¤mol-1

I2/KJ¡¤mol-1

I3/KJ¡¤mol-1

I4/KJ¡¤mol-1

I5/KJ¡¤mol-1

738

1451

7733

10540

13630

¢Ù¸Ã½ðÊôÔªËØÊÇ___________(ÌîÔªËØ·ûºÅ)£®£®

¢ÚÈôÇ⻯ÎïµÄ¾§°û½á¹¹ÈçͼËùʾ(ÓÐ4¸öHÔ­×ÓλÓÚÃæÉÏ£¬ÆäÓàHÔ­×ÓλÓÚ¾§°ûÄÚ)£¬ÒÑÖª¸Ã¾§ÌåµÄÃܶÈΪ¦Ñg¡¤cm-3,Ôò¸Ã¾§°ûµÄÌå»ýΪ__________cm3[Óú¬¦Ñ¡¢NAµÄ´úÊýʽ±íʾ(ÆäÖÐNAΪ°¢·ü¼ÓµÂÂÞ³£ÊýµÄÖµ)]¡£

¡¾ÌâÄ¿¡¿ÖйúÓйãÀ«µÄº£°¶Ïߣ¬½¨Éè·¢Õ¹º£Ñ󾭼ᢺ£Ë®µÄ×ÛºÏÀûÓôóÓпÉΪ¡£

I£®¿ÕÆø´µ³ö·¨¹¤ÒÕ£¬ÊÇÄ¿Ç°¡°º£Ë®Ìáä塱µÄ×îÖ÷Òª·½·¨Ö®Ò»¡£Æ乤ÒÕÁ÷³ÌÈçÏÂͼËùʾ£¬ÊԻشðÏÂÁÐÎÊÌ⣺

£¨1£©ÒÔÉϲ½Öè¢ñÖÐÒÑ»ñµÃÓÎÀë̬µÄä壬²½Öè¢òÓÖ½«Ö®×ª±ä³É»¯ºÏ̬µÄä壬ÆäÄ¿µÄÊÇ____________¡£

£¨2£©²½Öè¢ÚͨÈëÈÈ¿ÕÆø»òË®ÕôÆø´µ³öBr2£¬ÀûÓÃÁËäåµÄ________¡£

A£®Ñõ»¯ÐÔ B£®»¹Ô­ÐÔ C£®»Ó·¢ÐÔ D£®¸¯Ê´ÐÔ

£¨3£©Á÷³Ì¢òÖÐÉæ¼°µÄÀë×Ó·´Ó¦·½³ÌʽÈçÏ£¬ÇëÔÚÏÂÃæºáÏßÄÚÌîÈëÊʵ±µÄ»¯Ñ§¼ÆÁ¿Êý£º

___Br2£«___=___£«___Br£­£«___CO2¡ü

£¨4£©ÉÏÊöÁ÷³ÌÖдµ³öµÄäåÕôÆø£¬Ò²¿ÉÏÈÓöþÑõ»¯ÁòË®ÈÜÒºÎüÊÕ£¬ÔÙÓÃÂÈÆøÑõ»¯ºóÕôÁó¡£Ð´³öäåÓë¶þÑõ»¯ÁòË®ÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º___________________¡£

£¨5£©Á÷³Ì¢óÕôÁó¹ý³ÌÖУ¬Î¶ÈÓ¦¿ØÖÆÔÚ80¡«90¡æ¡£Î¶ȹý¸ß»ò¹ýµÍ¶¼²»ÀûÓÚÉú²ú£¬Çë½âÊÍÔ­Òò£º_________¡£

¢ò£®Ä¿Ç°ÊÀ½çÉÏ60%µÄþÊÇ´Óº£Ë®ÖÐÌáÈ¡µÄ¡£º£Ë®ÌáþµÄÖ÷ÒªÁ÷³ÌÈçÏ£º

£¨6£©²Ù×÷AÊÇ_____________£¬ÊÔ¼ÁaÊÇ_____________

£¨7£©ÓÉÎÞË®MgCl2ÖÆÈ¡MgµÄ»¯Ñ§·½³ÌʽÊÇ________________________¡£´Ó¿¼Âdzɱ¾ºÍ·ÏÎïÑ­»·ÀûÓõĽǶȣ¬¸±²úÎï¿ÉÒÔÓÃÓÚ_____________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø