ÌâÄ¿ÄÚÈÝ
ÒÑÖªH2(g)£«1/2O2(g)===H2O(g) ¦¤H£½£241.8 kJ¡¤mol£1ÏÂÁÐ˵·¨Öв»ÕýÈ·µÄÊÇ( )
A£®H2µÄȼÉÕÈÈΪ241.8 kJ¡¤mol£1 |
B£®2H2(g)£«O2(g)===2H2O(g)¦¤H£½£483.6 kJ¡¤mol£1 |
C£®1 mol H2ÍêȫȼÉÕÉú³ÉҺ̬ˮ·Å³öµÄÈÈÁ¿´óÓÚ241.8 kJ |
D£®¶ÏÁÑ1 mol H2OµÄ»¯Ñ§¼üÎüÊÕµÄ×ÜÄÜÁ¿´óÓÚ¶ÏÁÑ1 mol H2ºÍ0.5 mol O2µÄ»¯Ñ§¼üËùÎüÊÕµÄ×ÜÄÜÁ¿ |
A
ÊÔÌâ·ÖÎö£ºÈ¼ÉÕÈÈÊÇÔÚÒ»¶¨Ìõ¼þÏ£¬1mol¿ÉȼÎïÍêȫȼÉÕÉú³ÉÎȶ¨µÄÑõ»¯ÎïʱËù·Å³öµÄÈÈÁ¿£¬ËùÒÔA²»ÕýÈ·£¬Ë®µÄÎȶ¨×´Ì¬ÊÇҺ̬£»·´Ó¦ÈȺͻ¯Ñ§¼ÆÁ¿Êý³ÉÕý±È£¬BÕýÈ·£»Æø̬ˮµÄÄÜÁ¿¸ßÓÚҺ̬ˮµÄÄÜÁ¿£¬ËùÒÔ1 mol H2ÍêȫȼÉÕÉú³ÉҺ̬ˮ·Å³öµÄÈÈÁ¿´óÓÚ241.8 kJ£¬CÕýÈ·£»·´Ó¦ÈÈ»¹µÈÓڶϼüÎüÊÕµÄÄÜÁ¿ºÍÐγɻ¯Ñ§¼üËù·Å³öµÄÄÜÁ¿µÄ²îÖµ£¬DÕýÈ·£¬´ð°¸Ñ¡A¡£
¿¼µã£»¿¼²é·´Ó¦ÈȵÄÓйØÅжÏ
µãÆÀ£º´Óºê¹ÛµÄ½Ç¶È·ÖÎö£¬·´Ó¦ÈȾÍÊÇ·´Ó¦ÎïºÍÉú³ÉÎï×ÜÄÜÁ¿µÄÏà¶Ô´óС£¬¶ø´Ó΢¹ÛµÄ½Ç¶È·ÖÎö£¬·´Ó¦ÈȾÍÊǶϼüÎüÊÕµÄÄÜÁ¿ºÍÐγɻ¯Ñ§¼üËù·Å³öµÄÄÜÁ¿µÄ²îÖµ¡£ÁíÍ⻹ÐèҪעÒâµÄÊÇ·´Ó¦ÈÈ»¹ÓëÎïÖʵÄ״̬ÓйØϵ£¬ÔÚÅжÏʱÐèҪעÒâ¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿