ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿¢ñ£©
£¨1£©ÊµÑéÖÐÄܹ۲쵽µÄÏÖÏóÊÇ____________________¡££¨Ñ¡Ìî´úºÅ£©
A£®ÊÔ¹ÜÖÐþƬÖð½¥Èܽâ B£®ÊÔ¹ÜÖвúÉúÎÞÉ«ÆøÅÝ
C£®ÉÕ±Íâ±Ú±äÀä D£®ÉÕ±µ×²¿Îö³öÉÙÁ¿°×É«¹ÌÌå
£¨2£©ÓÉʵÑéÍÆÖª£¬MgCl2ÈÜÒººÍH2µÄ×ÜÄÜÁ¿________£¨Ìî¡°´óÓÚ¡±¡°Ð¡ÓÚ¡±¡°µÈÓÚ¡±£©Ã¾Æ¬ºÍÑÎËáµÄ×ÜÄÜÁ¿¡£
¢ò£©ÓÃ50mL0.50mol/LÑÎËáÓë50mL0.55mol/LNaOHÈÜÒºÔÚÈçͼËùʾµÄ×°ÖÃÖнøÐÐÖкͷ´Ó¦¡£Í¨¹ý²â¶¨·´Ó¦¹ý³ÌÖÐËù·Å³öµÄÈÈÁ¿¿É¼ÆËãÖкÍÈÈ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©´ÓʵÑé×°ÖÃÉÏ¿´£¬Í¼ÖÐÉÐȱÉÙµÄÒ»ÖÖ²£Á§ÓÃÆ·ÊÇ___________£¬³ý´ËÖ®Í⻹ÓÐÒ»´¦´íÎóµÄÊÇ____________________¡£
£¨2£©´óÉÕ±ÉÏÈç²»¸ÇÓ²Ö½°å£¬ÇóµÃµÄÖкÍÈÈÊýÖµ£¨¾ø¶ÔÖµ£©__________£¨Ìî¡°Æ«´ó¡¢Æ«Ð¡¡¢ÎÞÓ°Ï족£©¡£
¢ó£©£¨1£©ÃºÈ¼Éյķ´Ó¦ÈÈ¿Éͨ¹ýÒÔÏÂÁ½¸ö;¾¶À´ÀûÓãºa.ÀûÓÃúÔÚ³ä×ãµÄ¿ÕÆøÖÐÖ±½ÓȼÉÕ²úÉúµÄ·´Ó¦ÈÈ£»b.ÏÈʹúÓëË®ÕôÆø·´Ó¦µÃµ½ÇâÆøºÍÒ»Ñõ»¯Ì¼£¬È»ºóʹµÃµ½µÄÇâÆøºÍÒ»Ñõ»¯Ì¼ÔÚ³ä×ãµÄ¿ÕÆøÖÐȼÉÕ¡£ÕâÁ½¸ö¹ý³ÌµÄÈÈ»¯Ñ§·½³ÌʽΪ£º
a£®C£¨s£©£«O2£¨g£©===CO2£¨g£© ¦¤H£½E1 ¢Ù
b£®C£¨s£©£«H2O£¨g£©===CO£¨g£©£«H2£¨g£©¦¤H£½E2 ¢Ú
H2£¨g£©£«1/2O2£¨g£©===H2O£¨g£©¦¤H£½E3 ¢Û
CO£¨g£©£«1/2O2£¨g£©===CO2£¨g£©¦¤H£½E4 ¢Ü
Çë±í´ïE1¡¢E2¡¢E3¡¢E4Ö®¼äµÄ¹ØϵΪE2£½_________________¡£
£¨2£©ÈçͼËùʾÔÚ³£Î³£Ñ¹Ï£¬1Ħ¶ûNO2 ºÍ1Ħ¶ûCOÍêÈ«·´Ó¦Éú³ÉCO2ºÍNO¹ý³ÌÖÐÄÜÁ¿±ä»¯Ê¾Òâͼ£¬Çëд³öNO2ºÍCO·´Ó¦µÄÈÈ»¯Ñ§·½³Ìʽ£º___________________¡£
£¨3£©»¯Ñ§·´Ó¦µÄìʱäÓë·´Ó¦ÎïºÍÉú³ÉÎïµÄ¼üÄÜÓйء£ÒÑ֪ijЩ»¯Ñ§¼üµÄ¼üÄÜÈçϱíËùʾ£º
¹²¼Û¼ü | H¡ªH | Cl¡ªCl | H¡ªCl |
¼üÄÜ/£¨kJ¡¤mol£1£© | 436 | 247 | 434 |
Ôò·´Ó¦£ºH2£¨g£©+Cl2£¨g£©=2HCl£¨g£©µÄìʱ䦤H £½ ____________________¡£
¡¾´ð°¸¡¿A B DСÓÚ»·Ðβ£Á§½Á°è°ôСÉÕ±¿ÚºÍ´óÉÕ±¿ÚûÓÐƽÆ루ÆäËüºÏÊʴ𰸸ø·Ö£©Æ«Ð¡E2£½E1£E3£E4NO2£¨g£©+CO£¨g£©=NO£¨g£©+CO2£¨g£© ¦¤H£½£234 kJ¡¤mol£1¦¤H £½£185 kJ¡¤mol£1
¡¾½âÎö¡¿
¢ñ)(1)þÓëÑÎËá¾çÁÒ·´Ó¦£¬²úÉúÇâÆø²¢·Å³ö´óÁ¿µÄÈÈ£¬ÓÉÓÚÇâÑõ»¯¸ÆµÄÈܽâ¶ÈËæζÈÉý¸ß¶ø¼õС£¬ËùÒÔ±¥ºÍʯ»ÒË®ÉýκóÎö³öµÄÇâÑõ»¯¸ÆʹÈÜÒº³Ê»ë×Ç×´£¬Ã¾ÌõÈܽ⣬¹ÊABDÑ¡ÏîÖеÄÏÖÏó·ûºÏ£»¹Ê´ð°¸Îª£ºABD£»
(2)µ±·´Ó¦ÎïµÄÄÜÁ¿¸ßÓÚÉú³ÉÎïµÄÄÜÁ¿Ê±£¬·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£¬¹ÊMgCl2ÈÜÒººÍH2µÄ×ÜÄÜÁ¿Ð¡ÓÚþƬµÄÑÎËáµÄ×ÜÄÜÁ¿£¬¹Ê´ð°¸Îª£ºÐ¡ÓÚ£»
¢ò)(1)ÓÉÁ¿ÈȼƵĹ¹Ôì¿ÉÖª¸Ã×°ÖõÄȱÉÙÒÇÆ÷ÊÇ»·Ðβ£Á§½Á°è°ô£»ÖкÍÈȲⶨʵÑé³É°ÜµÄ¹Ø¼üÊDZ£Î¹¤×÷£¬ÄÚÍâÉձΪһÑù¸ß£¬·ñÔò£¬ÈÈÁ¿É¢Ê§´ó£»¹Ê´ð°¸Îª£º»·Ðβ£Á§½Á°è°ô£»Ð¡ÉÕ±¿ÚºÍ´óÉÕ±¿ÚûÓÐƽÆ룻
(2)´óÉÕ±ÉÏÈç²»¸ÇÓ²Ö½°å£¬»áÓÐÒ»²¿·ÖÈÈÁ¿É¢Ê§£¬ÇóµÃµÄÖкÍÈÈÊýÖµ½«»á¼õС£¬¹Ê´ð°¸Îª£ºÆ«Ð¡£»
¢ó)(1)¢ÙC(s)+O2(g)¨TCO2(g)¡÷H=E1£¬¢ÛH2(g)+O2(g)¨TH2O(g)¡÷H=E3£¬¢ÜCO(g)+O2(g)¨TCO2(g)¡÷H=E4£¬¸ù¾Ý¸Ç˹¶¨ÂÉ£¬¢Ù-¢Û-¢Ü¿ÉµÃ£ºC(s)+H2O(g)¨TCO(g)+H2(g)£¬¹ÊE2=E1-E3-E4£¬¹Ê´ð°¸Îª£ºE1-E3-E4£»
(2)ÓÉͼ¿ÉÖª£¬1Ħ¶ûNO2ºÍ1Ħ¶ûCOÍêÈ«·´Ó¦Éú³ÉCO2ºÍNO·Å³öÈÈÁ¿Îª(368-134)kJ=234kJ£¬·´Ó¦ÈÈ»¯Ñ§·½³ÌʽΪ£ºNO2(g)+CO(g)¨TNO(g)+CO2(g)¡÷H=-234 kJmol-1£¬¹Ê´ð°¸Îª£ºNO2(g)+CO(g)¨TNO(g)+CO2(g)¡÷H=-234 kJmol-1£»
(3)·´Ó¦ÈÈ=·´Ó¦Îï×ܼüÄÜ-Éú³ÉÎï×ܼüÄÜ£¬¹Ê·´Ó¦£ºH2(g)+Cl2(g)¨T2HCl(g)µÄìʱä¡÷H=436kJ/mol+247kJ/mol-2¡Á434kJ/mol=-185kJ/mol£¬¹Ê´ð°¸Îª£º-185 kJ/mol¡£