ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ºÏ³É°±ÊÇÈËÀà¿Æѧ¼¼Êõ·¢Õ¹Ê·ÉϵÄÒ»ÏîÖØ´óÍ»ÆÆ£¬Ñо¿±íÃ÷Òº°±ÊÇÒ»ÖÖÁ¼ºÃµÄ´¢ÇâÎïÖÊ¡£
(1) °±Æø·Ö½â·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º2NH3(g) N2(g)£«3H2(g)¡¡¦¤H
Èô£ºN¡ÔN¼ü¡¢H£H¼üºÍN£H¼üµÄ¼üÄÜ·Ö±ð¼Ç×÷a¡¢bºÍc(µ¥Î»£ºkJ¡¤mol1)ÔòÉÏÊö·´Ó¦µÄ¦¤H£½________kJ¡¤mol1¡£
(2) Ñо¿±íÃ÷½ðÊô´ß»¯¼Á¿É¼ÓËÙ°±ÆøµÄ·Ö½â¡£Ï±íΪijζÈϵÈÖÊÁ¿µÄ²»Í¬½ðÊô·Ö±ð´ß»¯µÈŨ¶È°±Æø·Ö½âÉú³ÉÇâÆøµÄ³õʼËÙÂÊ(mmol¡¤min1)¡£
´ß»¯¼Á | Ru | Rh | Ni | Pt | Pd | Fe |
³õʼËÙÂÊ | 7.9 | 4.0 | 3.0 | 2.2 | 1.8 | 0.5 |
¢Ù²»Í¬´ß»¯¼Á´æÔÚÏ£¬°±Æø·Ö½â·´Ó¦»î»¯ÄÜ×î´óµÄÊÇ________(Ìîд´ß»¯¼ÁµÄ»¯Ñ§Ê½)¡£
¢ÚζÈΪT£¬ÔÚÒ»Ìå»ý¹Ì¶¨µÄÃܱÕÈÝÆ÷ÖмÓÈë2 mol NH3£¬´ËʱѹǿΪP0£¬ÓÃRu´ß»¯°±Æø·Ö½â£¬Èôƽºâʱ°±Æø·Ö½âµÄת»¯ÂÊΪ50%£¬Ôò¸ÃζÈÏ·´Ó¦2NH3(g) N2(g)£«3H2(g)ÓÃƽºâ·Öѹ´úÌæƽºâŨ¶È±íʾµÄ»¯Ñ§Æ½ºâ³£ÊýKp£½________¡£[ÒÑÖª£ºÆøÌå·Öѹ(p·Ö)£½ÆøÌå×Üѹ(p×Ü)¡ÁÌå»ý·ÖÊý]
(3) ¹ØÓںϳɰ±¹¤ÒÕµÄÀí½â£¬ÏÂÁÐÕýÈ·µÄÊÇ________¡£
A£®ºÏ³É°±¹¤Òµ³£²ÉÓõķ´Ó¦Î¶ÈΪ500¡æ×óÓÒ£¬¿ÉÓÃÀÕÏÄÌØÁÐÔÀí½âÊÍ
B£®Ê¹Óóõʼ·´Ó¦ËÙÂʸü¿ìµÄ´ß»¯¼ÁRu£¬²»ÄÜÌá¸ßƽºâʱNH3µÄ²úÁ¿Î
C£®ºÏ³É°±¹¤Òµ²ÉÓÃ10 MPa¡«30 MPa£¬ÊÇÒò³£Ñ¹ÏÂN2ºÍH2µÄת»¯Âʲ»¸ß
D£®²ÉÓÃÀäË®½µÎµķ½·¨¿É½«ºÏ³Éºó»ìºÏÆøÌåÖеݱҺ»¯
(4) ÔÚ1 L 1 mol¡¤L1µÄÑÎËáÖлº»ºÍ¨Èë2 mol°±Æø£¬ÇëÔÚͼÖл³öÈÜÒºÖÐË®µçÀë³öµÄOHŨ¶ÈËæ°±ÆøͨÈë±ä»¯µÄÇ÷ÊÆͼ¡£______________________________
(5) µç»¯Ñ§·¨Ò²¿ÉºÏ³É°±¡£ÏÂͼÊÇÓõÍιÌÌåÖÊ×Óµ¼Ìå×÷Ϊµç½âÖÊ£¬ÓÃPtC3N4×÷Òõ¼«´ß»¯¼Áµç½âH2(g)ºÍN2(g)ºÏ³ÉNH3µÄÔÀíʾÒâͼ£º
¢ÙPtC3N4µç¼«·´Ó¦²úÉúNH3µÄµç¼«·´Ó¦Ê½________¡£
¢ÚʵÑéÑо¿±íÃ÷£¬µ±Íâ¼Óµçѹ³¬¹ýÒ»¶¨ÖµÒԺ󣬷¢ÏÖÒõ¼«²úÎïÖа±ÆøµÄÌå»ý·ÖÊýËæ×ŵçѹµÄÔö´ó¶ø¼õС£¬·ÖÎöÆä¿ÉÄÜÔÒò________¡£
¡¾´ð°¸¡¿6c£a£3b Fe BC
N2£«6e£«6H+=2NH3 ³¬¹ýÒ»¶¨µçѹÒÔºó£¬H+µÃµç×Ó±ä³ÉH2£¬¶øÇÒËÙÂʱȵªÆø¿ì
¡¾½âÎö¡¿
£¨1£©2NH3(g) N2(g)£«3H2(g)ÖУ¬N¡ÔNÓÐ1¸ö£¬N£HÓÐ6¸ö£¬H-HÓÐ3¸ö£¬¡÷H=·´Ó¦ÎïµÄ¼üÄÜÖ®ºÍ¡ªÉú³ÉÎïµÄ¼üÄÜÖ®ºÍ=6c£a£3b£»
£¨2£©½ðÊô´ß»¯¼Á¿É¼ÓËÙ°±ÆøµÄ·Ö½â£¬·´Ó¦Ô½Âý£¬ËµÃ÷·´Ó¦ËùÐèµÄ»î»¯ÄÜÔ½´ó£¬¾Ý±íËùÖª£¬Fe´ß»¯Ê±·´Ó¦ËÙÂÊ×îÂý£¬°±Æø·Ö½â·´Ó¦»î»¯ÄÜ×î´óµÄÊÇFe¡£
£¨3£©·´Ó¦2NH3(g) N2(g)£«3H2(g)¿ªÊ¼Ê±ÓÐ2 mol NH3£¬´ËʱѹǿΪP0£¬NH3µÄת»¯ÂÊΪ50%£¬·´Ó¦Æ½ºâʱÌåϵÄÚÓÐ1mol NH3£¬0.5mol N2ºÍ1.5mol H2£¬×ÜÎïÖʵÄÁ¿Îª3mol£¬ËùÒÔƽºâʱµÄ×ÜѹΪ
P0£¬µªÆøµÄ·ÖѹΪ
P0£¬ÇâÆøµÄ·ÖѹΪ
P0£¬°±ÆøµÄ·ÖѹΪ
P0£¬¹ÊKp=
=
£»
£¨4£©A. ºÏ³É°±µÄ·´Ó¦ÊÇ·ÅÈȵģ¬ËùÒԺϳɰ±Ê±Î¶ÈÔ½µÍ£¬°±µÄת»¯ÂÊÔ½¸ß¡£µ«Î¶ȹýµÍÔòÓ°Ïì´ß»¯¼ÁµÄ»îÐÔ£¬ÊÊÒËζÈΪ500¡æ£¬ºÍÀÕÏÄÌØÁÐÔÀíûÓйØϵ£¬¹ÊA´íÎó£»
B. ʹÓô߻¯¼Á²»Äܸı䷴Ӧ³Ì¶È£¬¹Ê²»ÄÜÌá¸ßƽºâʱNH3µÄ²úÁ¿£¬BÕýÈ·£»
C. ºÏ³É°±¹¤Òµ²ÉÓÃ10 MPa¡«30 MPa£¬ÊÇÒò³£Ñ¹ÏÂN2ºÍH2µÄת»¯Âʲ»¸ß£¬¹ÊCÕýÈ·£»
D. °±ÆøÒ×ÈÜÓÚË®£¬ËùÒÔ²»ÄܲÉÓÃÀäË®½µÎµķ½·¨¿É½«ºÏ³Éºó»ìºÏÆøÌåÖеݱҺ»¯£¬¹ÊD´íÎó£»
ÕýÈ·´ð°¸ÊÇBC¡£
£¨5£©¸Õ¿ªÊ¼Í¨ÈëNH3£¬NH3ºÍHCl·´Ó¦Éú³ÉÂÈ»¯ï§£¬´Ù½øË®µÄµçÀ룬µ±NH3µÄÁ¿´óÓÚ1molʱ£¬HCl·´Ó¦Í꣬Éú³É°±Ë®ÓÖÂýÂýÒÖÖÆË®µÄµçÀ룬ËùÒÔ´ð°¸Èçͼ£º
£¨6£©PtC3N4µç¼«²úÉú°±ÆøµÃµç×Ó£¬µç¼«·½³ÌʽΪ£ºN2£«6e£«6H+=2NH3£»µ±Íâ¼Óµçѹ³¬¹ýÒ»¶¨ÖµÒԺ󣬷¢ÏÖÒõ¼«²úÎïÖа±ÆøµÄÌå»ý·ÖÊýËæ×ŵçѹµÄÔö´ó¶ø¼õС£¬·ÖÎöÆä¿ÉÄÜÔÒòÊdz¬¹ýÒ»¶¨µçѹÒÔºó£¬H+µÃµç×Ó±ä³ÉH2£¬¶øÇÒËÙÂʱȵªÆø¿ì¡£
![](http://thumb2018.1010pic.com/images/loading.gif)
¡¾ÌâÄ¿¡¿ÈéËáÑÇÌú£¨[CH3CH(OH)COO]2Fe3H2O£¬Mr=288£©ÊÇÒ»ÖÖʳÓõIJ¹Ìú¼Á£¬ÎüÊÕЧ¹û±ÈÎÞ»úÌúºÃ£¬Ò×ÈÜÓÚË®£¬¼¸ºõ²»ÈÜÓÚÒÒ´¼£¬ÊÜÈÈÒ׷ֽ⣬¿Éͨ¹ýÈéËáÓë̼ËáÑÇÌú·´Ó¦ÖƵá£
CH3CH(OH)COOH+FeCO3+2H2O=[CH3CH(OH)COO]2Fe3H2O+CO2¡ü
FeCO3²»ÈÜÓÚË®£¬Ò×±»Ñõ»¯£¬4FeCO3+6H2O+O2=4Fe(OH)3+4CO2
¢ñ.ÈéËáÑÇÌúµÄÖƱ¸£º
ijÐËȤС×éÓÃFeCl2ºÍNH4HCO3ÖƱ¸FeCO3µÄ×°ÖÃʾÒâͼÈçͼ£º
»Ø´ðÏÂÁÐÎÊÌ⣺
(1)C×°ÖÃÖÐÉæ¼°µÄÖ÷Òª·´Ó¦µÄÀë×Ó·½³Ìʽ_________¡£
(2)´ýD´¦µÄÆøÌå´¿¾»ºó£¬½«Éú³ÉµÄFeCl2ÈÜÒººÍNH4HCO3ÈÜÒº»ìºÏʱµÄ²Ù×÷ÊÇ_____¡£
(3)½«ÖƵõÄFeCO3¼ÓÈëµ½×ãÁ¿ÈéËáÈÜÒºÖУ¬ÔÙ¼ÓÈëÉÙÁ¿Ìú·Û£¬75¡æϽÁ°è·´Ó¦¡£¼ÓÈëÉÙÁ¿Ìú·ÛµÄ×÷ÓÃÊÇ_______¡£
(4)·´Ó¦½áÊøºó£¬ÎÞÐè¹ýÂË£¬³ýÈ¥¹ýÁ¿Ìú·ÛµÄ·½·¨ÊÇ_________¡£
(5)´ÓËùµÃÈÜÒºÖлñµÃÈéËáÑÇÌú¾§ÌåµÄ·½·¨ÊÇ£º________£¬ÀäÈ´½á¾§£¬¹ýÂË£¬ ÓÃÊÊÁ¿ÒÒ´¼Ï´µÓ£¬¸ÉÔï¡£
¢ò.ÈéËáÑÇÌú¾§Ìå´¿¶ÈµÄ²âÁ¿£º
(6)¸ÃÐËȤС×éÓÃKMnO4µÎ¶¨·¨²â¶¨ÑùÆ·ÖÐÑÇÌúº¬Á¿½ø¶ø¼ÆËã²úÆ·ÖÐÈéËáÑÇÌúµÄÖÊÁ¿·ÖÊý£¬·¢ÏÖ²úÆ·µÄÖÊÁ¿·ÖÊý×ÜÊÇ´óÓÚ100%£¬ÆäÔÒò¿ÉÄÜÊÇ___¡£
(7)¾²éÔÄÎÄÏ׺󣬸ÃÐËȤС×é¸ÄÓÃîæ(Ce)Á¿·¨²â¶¨²úÆ·ÖÐFe2+µÄº¬Á¿£¬µÎ¶¨·´Ó¦ÈçÏ£ºCe4++Fe2+=Ce3++Fe3+¡£È¡1.440g²úÆ·Åä³É100mLÈÜÒº£¬Ã¿´ÎÈ¡20.00mL£¬½øÐбØÒª´¦Àí£¬ÓÃ0.0500molL-1Ce(SO4)2±ê×¼ÈÜÒºµÎ¶¨ÖÁÖյ㣬¼Ç¼Êý¾ÝÈç±í¡£
µÎ¶¨´ÎÊý | µÎ¶¨Ç°¶ÁÊý£¨mL£© | µÎ¶¨ºó¶ÁÊý£¨mL£© |
1 | 0.20 | 19.95 |
2 | 0.10 | 21.65 |
3 | 0.95 | 20.60 |
Ôò²úÆ·ÖÐÈéËáÑÇÌúµÄÖÊÁ¿·ÖÊýΪ________%¡£(СÊýµãºó±£ÁôһλÊý×Ö)
(8)ÇëÉè¼ÆʵÑéÖ¤Ã÷Ä㹺ÂòµÄÈéËáÑÇÌú²¹Ìú¼ÁÖк¬Fe2+£º_______¡£