ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿±¡ºÉÓÍÖк¬ÓÐÉÙÁ¿µÄ¦Á·ÇÀ¼ÌþºÍ¦Â·ÇÀ¼Ìþ£¬Á½Õß»¥ÎªÍ¬·ÖÒì¹¹Ì壬ÆäÏà¶Ô·Ö×ÓÖÊÁ¿Îª136¡£¸ù¾ÝÈçÏÂת»¯£¬»Ø´ðÏà¹ØÎÊÌ⣺

ÒÑÖª£º

£«RCHO

£«CO2

2CH3COOH

(1) д³ö¦Á·ÇÀ¼ÌþÖйÙÄÜÍÅÃû³Æ________£¬¦Â·ÇÀ¼ÌþµÄ½á¹¹¼òʽ________¡£

(2) ÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ________¡£

A£®¦Á·ÇÀ¼ÌþÓëµÈÎïÖʵÄÁ¿µÄBr2½øÐмӳɷ´Ó¦£¬²úÎï¹²ÓÐ3ÖÖ

B£®C¡úDºÍE¡úF·´Ó¦ÀàÐÍÏàͬ

C£®¾ÛºÏÎïHÒ×ÈÜÓÚË®

D£®C¡úM·´Ó¦¹ý³ÌÖÐÓи߷Ö×Ó¾ÛºÏÎïµÈ¸±²úÎï²úÉú

(3) д³öF¡úGµÄ»¯Ñ§·½³Ìʽ________¡£

(4) д³ö·ûºÏÏÂÁÐÌõ¼þµÄAµÄͬ·ÖÒì¹¹Ìå________¡£

¢Ùº¬ÓÐ4¸ö£­CH3£»¢Ú1 mol´Ëͬ·ÖÒì¹¹ÌåÔÚ¼îÐÔÌõ¼þÏÂË®½âÐè2 mol NaOH¡£

(5) ÒÔ¼×±½ºÍ±ûϩΪ»ù±¾Ô­ÁϺϳÉ(ÓÃÁ÷³Ìͼ±íʾ£¬ÆäËûÎÞ»úÊÔ¼ÁÈÎÑ¡)________¡£

¡¾´ð°¸¡¿Ì¼Ì¼Ë«¼ü AD CH2£½CHCOOH£«CH3OHCH2£½CHCOOCH3£«H2O ¡¡¡¡¡¡

¡¾½âÎö¡¿

¦Á·ÇÀ¼Ìþ·¢ÉúÐÅÏ¢ÖÐÑõ»¯·´Ó¦µÃµ½AÓëB£¬ÓëÇâÆø·¢Éú¼Ó³É·´Ó¦µÃµ½£¬A¼ÓÈÈÍÑË®Éú³É£¬ÔòAΪ£¬½áºÏAºÍµÄ½á¹¹£¬¿ÉÍÆÖª¦Á·ÇÀ¼ÌþΪ¡¢BΪ£¬BÓëÇâÆø·¢Éú¼Ó³É·´Ó¦Éú³ÉCΪ£¬CÓëHBr·¢ÉúÈ¡´ú·´Ó¦Éú³ÉDΪCH3CHBrCOOH£¬DÔÚÇâÑõ»¯ÄÆ´¼ÈÜÒº¡¢¼ÓÈÈÌõ¼þÏ·¢ÉúÏûÈ¥·´Ó¦¡¢Öкͷ´Ó¦µÃµ½EΪCH2£½CHCOONa£®EËữµÃµ½FΪCH2£½CHCOOH£¬FÓë¼×´¼·¢Éúõ¥»¯·´Ó¦µÃµ½GΪCH2£½CHCOOCH3£¬G·¢Éú¼Ó¾Û·´Ó¦µÃµ½HΪ£®ÓÉMµÄ·Ö×Óʽ£¬¿ÉÖª2·Ö×ÓC·¢Éúõ¥»¯·´Ó¦Ðγɻ·õ¥M£¬MµÄ½á¹¹¼òʽΪ¡£¾Ý´Ë·ÖÎö½â´ð¡£

£¨1£©¦Á·ÇÀ¼Ìþ·¢ÉúÐÅÏ¢ÖÐÑõ»¯·´Ó¦µÃµ½AÓëB£¬ÓëÇâÆø·¢Éú¼Ó³É·´Ó¦µÃµ½£¬½áºÏA¡¢µÄ½á¹¹£¬¿ÉÍÆÖª¦Á·ÇÀ¼ÌþΪ£¬¹ÙÄÜÍÅΪ£ºÌ¼Ì¼Ë«¼ü£»£«CO2£¬½áºÏ´ËÀà·´Ó¦¿ÉÖª¦Â·ÇÀ¼ÌþµÄ½á¹¹¼òʽΪ£»

£¨2£©A. ¸ÃÓлúÎïÖÐÁ½¸ö̼̼˫¼ü´¦ÓÚ¼ä룬ËüÓëµÈÎïÖʵÄÁ¿µÄBr2½øÐмӳɷ´Ó¦£¬ÓÐ3Öּӳɷ½Ê½£¬ËùÒÔÆä¼Ó³É²úÎïÓÐ3ÖÖ£¬¹ÊAÕýÈ·£»

B. C¡úDÊÇÈ¡´ú·´Ó¦£¬E¡úFÊÇË®½â·´Ó¦£¬¹ÊB´íÎó£»

C. ¾ÛºÏÎïHÖÐûÓÐôÇ»ù»òÕßôÈ»ù£¬²»Ò×ÈÜÓÚË®£¬¹ÊC´íÎó£»

D. ÓÉMµÄ·Ö×Óʽ£¬¿ÉÖª2·Ö×ÓC·¢Éúõ¥»¯·´Ó¦Ðγɻ·õ¥M£¬MµÄ½á¹¹¼òʽΪ£¬ ÖÐÓÐÒ»¸öôÈ»ùÒ»¸öôÇ»ù£¬¿ÉÒÔ·¢Éú¾ÛºÏ·´Ó¦£¬¹ÊDÕýÈ·£»¹ÊÑ¡AD¡£

£¨3£©FÓë¼×´¼·¢Éúõ¥»¯·´Ó¦µÃµ½GΪCH2£½CHCOOCH3£¬·½³ÌʽΪCH2£½CHCOOH£«CH3OHCH2£½CHCOOCH3£«H2O¡£

£¨4£©1 mol´Ëͬ·ÖÒì¹¹ÌåÔÚ¼îÐÔÌõ¼þÏÂË®½âÐè2 mol NaOH£¬ËµÃ÷ÓлúÎïÖÐÐèÒªÓÐÁ½¸ö̼ÑõË«¼ü£¬Í¬·ÖÒì¹¹ÌåΪ¡¡¡¡¡¡£»

£¨5£©ÒÔ¼×±½ºÍ±ûϩΪ»ù±¾Ô­ÁϺϳɣ¬¶ÔÕÕ¼×±½ºÍ²úÎïµÄ½á¹¹£¬½áºÏ¼×±½µÄÐÔÖÊ£¬Éè¼ÆÁ÷³ÌͼΪ£º¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿ºÏ³É°±ÊÇÈËÀà¿Æѧ¼¼Êõ·¢Õ¹Ê·ÉϵÄÒ»ÏîÖØ´óÍ»ÆÆ£¬Ñо¿±íÃ÷Òº°±ÊÇÒ»ÖÖÁ¼ºÃµÄ´¢ÇâÎïÖÊ¡£

(1) °±Æø·Ö½â·´Ó¦µÄÈÈ»¯Ñ§·½³ÌʽÈçÏ£º2NH3(g) N2(g)£«3H2(g)¡¡¦¤H

Èô£ºN¡ÔN¼ü¡¢H£­H¼üºÍN£­H¼üµÄ¼üÄÜ·Ö±ð¼Ç×÷a¡¢bºÍc(µ¥Î»£ºkJ¡¤mol1)ÔòÉÏÊö·´Ó¦µÄ¦¤H£½________kJ¡¤mol1¡£

(2) Ñо¿±íÃ÷½ðÊô´ß»¯¼Á¿É¼ÓËÙ°±ÆøµÄ·Ö½â¡£Ï±íΪijζÈϵÈÖÊÁ¿µÄ²»Í¬½ðÊô·Ö±ð´ß»¯µÈŨ¶È°±Æø·Ö½âÉú³ÉÇâÆøµÄ³õʼËÙÂÊ(mmol¡¤min1)¡£

´ß»¯¼Á

Ru

Rh

Ni

Pt

Pd

Fe

³õʼËÙÂÊ

7.9

4.0

3.0

2.2

1.8

0.5

¢Ù²»Í¬´ß»¯¼Á´æÔÚÏ£¬°±Æø·Ö½â·´Ó¦»î»¯ÄÜ×î´óµÄÊÇ________(Ìîд´ß»¯¼ÁµÄ»¯Ñ§Ê½)¡£

¢ÚζÈΪT£¬ÔÚÒ»Ìå»ý¹Ì¶¨µÄÃܱÕÈÝÆ÷ÖмÓÈë2 mol NH3£¬´ËʱѹǿΪP0£¬ÓÃRu´ß»¯°±Æø·Ö½â£¬Èôƽºâʱ°±Æø·Ö½âµÄת»¯ÂÊΪ50%£¬Ôò¸ÃζÈÏ·´Ó¦2NH3(g) N2(g)£«3H2(g)ÓÃƽºâ·Öѹ´úÌæƽºâŨ¶È±íʾµÄ»¯Ñ§Æ½ºâ³£ÊýKp£½________¡£[ÒÑÖª£ºÆøÌå·Öѹ(p·Ö)£½ÆøÌå×Üѹ(p×Ü)¡ÁÌå»ý·ÖÊý]

(3) ¹ØÓںϳɰ±¹¤ÒÕµÄÀí½â£¬ÏÂÁÐÕýÈ·µÄÊÇ________¡£

A£®ºÏ³É°±¹¤Òµ³£²ÉÓõķ´Ó¦Î¶ÈΪ500¡æ×óÓÒ£¬¿ÉÓÃÀÕÏÄÌØÁÐÔ­Àí½âÊÍ

B£®Ê¹Óóõʼ·´Ó¦ËÙÂʸü¿ìµÄ´ß»¯¼ÁRu£¬²»ÄÜÌá¸ßƽºâʱNH3µÄ²úÁ¿Î­

C£®ºÏ³É°±¹¤Òµ²ÉÓÃ10 MPa¡«30 MPa£¬ÊÇÒò³£Ñ¹ÏÂN2ºÍH2µÄת»¯Âʲ»¸ß

D£®²ÉÓÃÀäË®½µÎµķ½·¨¿É½«ºÏ³Éºó»ìºÏÆøÌåÖеݱҺ»¯

(4) ÔÚ1 L 1 mol¡¤L1µÄÑÎËáÖлº»ºÍ¨Èë2 mol°±Æø£¬ÇëÔÚͼÖл­³öÈÜÒºÖÐË®µçÀë³öµÄOHŨ¶ÈËæ°±ÆøͨÈë±ä»¯µÄÇ÷ÊÆͼ¡£______________________________

(5) µç»¯Ñ§·¨Ò²¿ÉºÏ³É°±¡£ÏÂͼÊÇÓõÍιÌÌåÖÊ×Óµ¼Ìå×÷Ϊµç½âÖÊ£¬ÓÃPtC3N4×÷Òõ¼«´ß»¯¼Áµç½âH2(g)ºÍN2(g)ºÏ³ÉNH3µÄÔ­ÀíʾÒâͼ£º

¢ÙPtC3N4µç¼«·´Ó¦²úÉúNH3µÄµç¼«·´Ó¦Ê½________¡£

¢ÚʵÑéÑо¿±íÃ÷£¬µ±Íâ¼Óµçѹ³¬¹ýÒ»¶¨ÖµÒԺ󣬷¢ÏÖÒõ¼«²úÎïÖа±ÆøµÄÌå»ý·ÖÊýËæ×ŵçѹµÄÔö´ó¶ø¼õС£¬·ÖÎöÆä¿ÉÄÜÔ­Òò________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø