ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Åð¼°Æ仯ºÏÎïÓ¦Óù㷺¡£»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©»ù̬BÔ×ӵļ۵ç×Ó¹ìµÀ±í´ïʽΪ________£¬ÆäµÚÒ»µçÀëÄܱÈBe ________£¨Ìî¡°´ó¡±»ò¡°Ð¡¡±£©¡£
£¨2£©°±ÅðÍ飨NH3BH3£©±»ÈÏΪÊÇ×î¾ßDZÁ¦µÄÐÂÐÍ´¢Çâ²ÄÁÏÖ®Ò»£¬·Ö×ÓÖдæÔÚÅäλ¼ü£¬Ìṩ¹Âµç×ӶԵijɼüÔ×ÓÊÇ________£¬Ð´³öÒ»ÖÖÓë°±ÅðÍ黥ΪµÈµç×ÓÌåµÄ·Ö×Ó________£¨Ìѧʽ£©¡£
£¨3£©³£Î³£Ñ¹ÏÂÅðËᣨH3BO3£©¾§Ìå½á¹¹Îª²ã×´£¬Æä¶þάƽÃæ½á¹¹Èçͼa¡£
¢Ù BÔ×ÓµÄÔÓ»¯·½Ê½Îª________¡£´ÓÇâ¼üµÄ½Ç¶È½âÊÍÅðËáÔÚÀäË®ÖеÄÈܽâ¶ÈС¶ø¼ÓÈÈʱÈܽâ¶ÈÔö´ó£º________¡£
¢Ú ·Ò×˹Ëá¼îÀíÂÛÈÏΪ£¬ÈκοɽÓÊܵç×ӶԵķÖ×Ó»òÀë×ӽзÒ×˹ËᣬÈκοɸø³öµç×ӶԵķÖ×Ó»òÀë×ӽзÒ×˹¼î¡£´Ó½á¹¹½Ç¶È·ÖÎöÅðËáÊÇ·Ò×˹Ë᣺________¡£
£¨4£©Á¢·½µª»¯Åð£¨BN£©ÊÇÌØÊâµÄÄÍÄ¥ºÍÇÐÏ÷²ÄÁÏ£¬Æ侧°û½á¹¹Óë½ð¸ÕʯÏàËÆ£¬ÈçͼbËùʾ¡£
¢Ù Ó뵪Ô×ÓÖ±½ÓÁ¬½ÓµÄÅðÔ×Ó¹¹³ÉµÄ¼¸ºÎÐÎ״Ϊ________¡£ÅðÔ×Ӻ͵ªÔ×ÓËùÁ¬½ÓµÄ×îС»·Îª________Ôª»·¡£
¢Ú ¾§°ûÓÐÁ½¸ö»ù±¾ÒªËØ£º
Ô×Ó×ø±ê²ÎÊý£¬±íʾ¾§°ûÄÚ²¿¸÷Ô×ÓµÄÏà¶ÔλÖá£ÈçͼbËùʾ£¬ÆäÖÐÔ×Ó×ø±ê²ÎÊýXΪ£¨0£¬0£¬0£©£¬YÔ×ÓµÄ×ø±ê²ÎÊýΪ£¨1/2£¬0£¬1/2£©£¬ÔòZÔ×ÓµÄ×ø±ê²ÎÊýΪ________¡£
¾§°û²ÎÊý£¬ÃèÊö¾§°ûµÄ´óСºÍÐÎ×´¡£ÒÑÖªÁ¢·½µª»¯ÅðµÄÃܶÈΪd gcm£3£¬°¢·ü¼ÓµÂÂÞ³£ÊýֵΪNA£¬Ôò¾§°û²ÎÊýa£½________nm¡££¨Áгö¼ÆËãʽ¼´¿É£©
¡¾´ð°¸¡¿ С N C2H6 sp2 ÅðËá·Ö×Ó¼äͨ¹ýÇâ¼üµÞºÏ£¬¼ÓÈÈʱ²¿·ÖÇâ¼ü±»ÆÆ»µ¡£ ÅðËá·Ö×ÓÖÐBÔ×ÓÓÐÒ»¸ö2p¿Õ¹ìµÀ¡£ ÕýËÄÃæÌå Áù (£¬ £¬ )
¡¾½âÎö¡¿£¨1£©BÔ×ÓÔ×ÓºËÄÚ5¸öÖÊ×Ó£¬»ù̬BÔ×Óµç×ÓÅŲ¼Ê½ÊÇ£º1s22s22p1£¬ËùÒÔ»ù̬BÔ×ӵļ۵ç×Ó¹ìµÀ±í´ïʽΪ£º£»BÔ×Ó¼Ûµç×ÓÅŲ¼Îª2s22p1£¬BeÔ×Ó¼Ûµç×ÓÅŲ¼Îª2s2£¬ËäÈ»pÄܼ¶ÄÜÁ¿½Ï¸ß£¬µ«¸ù¾Ý"ºéÌعæÔò"£¬µÈ¼Û¹ìµÀÈ«Âú»òÕß°ëÂú»òÕßÈ«¿ÕÊÇÏà¶ÔÎȶ¨µÄ½á¹¹£¬¹ÊBµÚÒ»µçÀëÄܱÈBeС¡£
£¨2£©°±ÅðÍ飨NH3BH3£©ÖУ¬NºÍBµÄ»¯ºÏ¼Û¶¼ÊÇ-3£¬BH3ÓëNH3µÄ»¯ºÏ¼Û¶¼ÊÇ0£¬Á½ÕßÖ®¼äÊÇͨ¹ýÅäλ¼üÏàÁ¬µÄµÄ£¬BµÄ×îÍâ²ãÓÐÈý¸öµç×Ó£¬½áºÏÈý¸öHÔ×Ó£¬»¹È±ÉÙÁ½¸öµç×ӾʹïÎȶ¨½á¹¹£¬¶øN½áºÏÈý¸öH»¹ÓÐÒ»¸ö¹Âµç×Ó¶Ô£¬ËùÒÔNÌṩ¹Âµç×Ó¶Ô¶øBÌṩ¿Õ¹ìµÀÐγÉÅäλ¼ü£»µÈµç×ÓÌå¾ßÓÐÏàͬµÄµç×ÓÊýÄ¿ºÍÔ×ÓÊýÄ¿£¬C2H6Óë°±ÅðÍ黥ΪµÈµç×ÓÌå¡£
£¨3£©¢ÙÅðÔ×Ó×îÍâ²ãÖ»ÓÐ3¸öµç×Ó£¬ÓëÑõÔ×ÓÐγÉ3¶Ô¹²Óõç×Ó¶Ô£¬¼Û²ãµç×Ó¶ÔΪ3£¬ÔÓ»¯¹ìµÀÊýΪ3£¬ÔÓ»¯ÀàÐÍΪsp2£»²ãÄÚµÄH3BO3·Ö×ÓÖ®¼äÖ÷Ҫͨ¹ýÇâ¼üÏàÁ¬£¬¼ÓÈÈʱ²¿·ÖÇâ¼üÈÝÒ×±»ÆÆ»µ£¬ËùÒÔÅðËáÔÚÀäË®ÖеÄÈܽâ¶ÈС¶ø¼ÓÈÈʱÈܽâ¶ÈÔö´ó¡£¢ÚÅðËá·Ö×ÓÖÐÐĵÄBÔ×Ósp2ÔÓ»¯£¬ÓÐ3¸ösp2ºÍ1¸ö2p¹ìµÀ£¬¹ìµÀ×ÜÊý¾ÍÊÇ4£»BÓÐ3¸ö¼Ûµç×Ó£¬·Ö±ðÔÚ3¸ösp2¹ìµÀÖкÍÑõ³É¼ü£¬ÄÇô³É¼üÊýÄ¿ÊÇ3£»ÅðµÄµç×Ó¶¼ÓõôÁË£¬ËùÒÔûÓй¶Եç×Ó£¬ÄÇô¾ÍÓÐÒ»¸ö¿Õ¹ìµÀ£¬Ò²¾ÍÊÇ2P¿Õ¹ìµÀ£¬¸ù¾Ý·Ò×˹Ëá¼îÀíÂÛ£ºÈκοɽÓÊܵç×ӶԵķÖ×Ó»òÀë×ӽзÒ×˹ËᣬËùÒÔÅðËáÊÇ·Ò×˹Ëá¡£
£¨4£©¢ÙÁ¢·½µª»¯Åð£¨BN£©Èçͼb£¬N(°×É«)Õ¼¾ÝÁ¢·½ÌåµÄ8¸ö¶¥µãºÍ6¸öÃæÐÄ£¬ËùÒÔÓÐ8¡Á+6¡Á=4¸ö£»B(ºÚÉ«)Õ¼¾ÝСÁ¢·½Ì壨°Ë·ÖÖ®Ò»¸ö¾§°û£©µÄÖÐÐÄ£¬¹²4¸ö£¬ÔòÒ»¸ö¾§°ûÖÐÓÐ4¸öN£¬4¸öB£»Ó뵪Ô×ÓÖ±½ÓÁ¬½ÓµÄÅðÔ×Ó¹¹³ÉµÄ¼¸ºÎÐÎ״ΪÕýËÄÃæÌ壬ÆäÖеªÔ×ÓÔÚÌåÐÄ£¬4¸öÅðÔ×ÓÔÚ¶¥µã£»ÅðÔ×Ӻ͵ªÔ×ÓËùÁ¬½ÓµÄ×îС»·ÎªÁùÔª»·¡£¢ÚÔ×Ó×ø±ê²ÎÊý£¬±íʾ¾§°ûÄÚ²¿¸÷Ô×ÓµÄÏà¶ÔλÖá£ÈçͼbËùʾ£¬ÆäÖÐÔ×Ó×ø±ê²ÎÊýXΪ£¨0£¬0£¬0£©£¬YÔ×ÓµÄ×ø±ê²ÎÊýΪ£¨1/2£¬0£¬1/2£©£¬ZΪB(ºÚÉ«)Õ¼¾ÝСÁ¢·½Ì壨°Ë·ÖÖ®Ò»¸ö¾§°û£©µÄÖÐÐÄ£¬¿ÉÖªZ´¦ÓÚµ½¸÷¸öÃæµÄ´¦£¬ÔòZÔ×ÓµÄ×ø±ê²ÎÊýΪ(£¬ £¬ )¡£ÓÉÒÑÖªÁ¢·½µª»¯ÅðµÄÃܶÈΪd gcm£3£¬°¢·ü¼ÓµÂÂÞ³£ÊýֵΪNA£¬¾§°û²ÎÊýΪa£¬NµÄÏà¶ÔÔ×ÓÖÊÁ¿Îª14£¬BµÄÏà¶ÔÔ×ÓÖÊÁ¿Îª11£¬Ôò¸ù¾Ý¾§°ûµÄÖÊÁ¿ÁÐʽ£ºd¡Áa3=£¬ËùÒÔa= cm=¡Á107 nm¡£
¡¾ÌâÄ¿¡¿ÊµÑéÊÒÖƱ¸1£¬2¡ª¶þäåÒÒÍéµÄ·´Ó¦ÔÀíÈçÏ£ºCH3CH2OH CH2=CH2£«H2O£¬CH2=CH2£«Br2BrCH2CH2Br¡£ÓÃÉÙÁ¿µÄäåºÍ×ãÁ¿µÄÒÒ´¼ÖƱ¸l£¬2¡ª¶þäåÒÒÍéµÄ×°ÖÃÈçͼËùʾ£¬ÓйØÊý¾ÝÈçÏÂ±í£º
ÒÒ´¼ | 1£¬2¡ª¶þäåÒÒÍé | ÒÒÃÑ | |
״̬ | ÎÞÉ«ÒºÌå | ÎÞÉ«ÒºÌå | ÎÞÉ«ÒºÌå |
ÃܶÈ/g¡¤cm-3 | 0.79 | 2.2 | 0.71 |
·Ðµã/¡æ | 78.5 | 132 | 34.6 |
ÈÛµã/¡æ | £130 | 9 | £116 |
»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÅÔÚ×°ÖÃcÖÐÓ¦¼ÓÈë______£¨Ñ¡ÌîÐòºÅ£©£¬ÆäÄ¿µÄÊÇÎüÊÕ·´Ó¦ÖпÉÄÜÉú³ÉµÄËáÐÔÆøÌå¡£
¢ÙË® ¢ÚŨÁòËá ¢ÛÇâÑõ»¯ÄÆÈÜÒº ¢Ü±¥ºÍ̼ËáÇâÄÆÈÜÒº
¢Æ½«¶þäåÒÒÍé´Ö²úÆ·ÖÃÓÚ·ÖҺ©¶·ÖмÓË®£¬Õñµ´ºó¾²Ö㬲úÎïÓ¦ÔÚË®µÄ________²ã¡££¨Ìî¡°ÉÏ¡±»ò¡°Ï¡±£©
¢ÇÅжÏd¹ÜÖÐÖƱ¸¶þäåÒÒÍé·´Ó¦ÒѽáÊøµÄ×î¼òµ¥·½·¨ÊÇ_________________________¡£
¢ÈÈô²úÎïÖÐÓÐÉÙÁ¿Î´·´Ó¦µÄBr2£¬×îºÃÓÃ________£¨ÌîÕýÈ·Ñ¡ÏîÇ°µÄÐòºÅ£©Ï´µÓ³ýÈ¥¡£
¢ÙË® ¢ÚÇâÑõ»¯ÄÆÈÜÒº ¢Ûµâ»¯ÄÆÈÜÒº ¢ÜÒÒ´¼
¢ÉÒÔ1£¬2¡ª¶þäåÒÒÍéΪÔÁÏ£¬ÖƱ¸¾ÛÂÈÒÒÏ©£¬ÎªÁËÌá¸ßÔÁÏÀûÓÃÂÊ£¬ÓÐͬѧÉè¼ÆÁËÈçÏÂÁ÷³Ì£º1£¬2¡ª¶þäåÒÒÍéͨ¹ý£¨¢Ù£©·´Ó¦ÖƵ㨢ڣ©£¬¢Úͨ¹ý£¨¢Û£©·´Ó¦ÖƵÃÂÈÒÒÏ©£¬ÓÉÂÈÒÒÏ©ÖƵþÛÂÈÒÒÏ©¡£
¢Ù______________£¨Ìî·´Ó¦ÀàÐÍ£©£¬Æ仯ѧ·½³Ìʽ__________________¡£
¢Ú______________£¨Ìî·´Ó¦ÀàÐÍ£©¡£
¡¾ÌâÄ¿¡¿ÓÃÈçͼËùʾװÖýøÐÐÏÂÁÐʵÑ飺½«¢ÙÖÐÈÜÒºµÎÈë¢ÚÖУ¬Ô¤²âµÄÏÖÏóÓëʵ¼ÊÏà·ûµÄÊÇ
Ñ¡Ïî | ¢ÙÖÐÎïÖÊ | ¢ÚÖÐÎïÖÊ | Ô¤²â¢ÚÖеÄÏÖÏó |
A | ŨÑÎËá | MnO2 | ²úÉú»ÆÂÌÉ«ÆøÌå |
B | ŨÏõËá | ÓÃÉ°Ö½´òÄ¥¹ýµÄÂÁÌõ | ²úÉúºì×ØÉ«ÆøÌå |
C | ËữµÄFeCl2ÈÜÒº | H2O2ÈÜÒº | ÈÜÒº±ä³É×Ø»ÆÉ«£¬ÓÐÆøÅݲúÉú |
D | Fe2(SO4)3ÈÜÒº | Í·Û | ÈÜÒº±äÀ¶É«¡¢ÓкÚÉ«¹ÌÌå²úÉú |
A. A B. B C. C D. D
¡¾ÌâÄ¿¡¿ÒÔÁ¶Ð¿Ñ̳¾£¨Ö÷Òª³É·ÝΪZnO£¬º¬ÉÙÁ¿CuOºÍFeO£©ÎªÔÁÏ£¬¿ÉÒÔÖÆÈ¡Ñõ»¯Ð¿ºÍ½ðÊôп¡£
¢ñ.ÖÆÈ¡Ñõ»¯Ð¿Ö÷Òª¹¤ÒÕÈçÏ£º
ϱíÁгöÁËÏà¹Ø½ðÊôÀë×ÓÉú³ÉÇâÑõ»¯Îï³ÁµíµÄpH£¨¿ªÊ¼³ÁµíµÄpH°´½ðÊôÀë×ÓŨ¶ÈΪl.0mol/L¼ÆË㣩¡£
½ðÊôÀë×Ó | ¿ªÊ¼³ÁµíµÄpH | ³ÁµíÍêÈ«µÄpH |
Fe3+ | 1.1 | 3.2 |
Zn2+ | 5.2 | 6.4 |
Fe2+ | 5.8 | 8.8 |
£¨1£©ÎªÁ˼ӿ췴Ӧ£¬¡°ËáÈÜ¡±ÐèÒªÊʵ±¼ÓÈÈ£¬µ«Î¶Ȳ»ÒËÌ«¸ß£¬ÔÒòÊÇ_________¡£
£¨2£©¼ÓÈëH2O2ÈÜÒº·¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ_______¡£
£¨3£©Á÷³ÌͼÖУ¬ÎªÁ˽µµÍÈÜÒºµÄËá¶È£¬µ÷½ÚpH·¶Î§Îª_______£»ÈôÊÔ¼ÁXΪZn2(OH)2CO3£¬¼ÓÈëX³ýÔÓÖʵÄÀë×Ó·½³ÌʽΪ________¡£
£¨4£©ÒÑÖª£¬ÊÒÎÂÏ£¬Ksp[Fe(OH)3]=4.0¡Á10-38£¬µ±pH=3ʱ£¬ÈÜÒºÖÐc(Fe3+)Ϊ______¡£´ÓZnCl2ÈÜÒºÖÐÌáÈ¡ÎÞË®ZnCl2µÄ·½·¨ÊÇ__________.
¢ò.ÖÆÈ¡½ðÊôп²ÉÓüîÈܽâZnO(s)+2NaOH (aq)+H2O=Na2[Zn(OH)4](aq),È»ºóµç½â½þÈ¡Òº¡£
£¨5£©Á¶Ð¿Ñ̳¾²ÉÓüîÈÜ£¬¶ø²»²ÉÓÃËáÈܺóµç½â£¬Ö÷ÒªÔÒòÊÇ______¡£
£¨6£©ÒÔʯī×÷µç¼«µç½âʱ£¬Ñô¼«²úÉúµÄÆøÌåΪ______£»Òõ¼«µÄµç¼«·´Ó¦Îª______¡£