ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ô̲ØÔÚº£µ×µÄ´óÁ¿¡°¿Éȼ±ù¡±£¬Æ俪·¢ÀûÓÃÊǵ±Ç°½â¾öÄÜԴΣ»úµÄÖØÒª¿ÎÌâ¡£CH4(g)+2H2O(g)CO2(g)+4H2(g)¦¤H3=+akJ¡¤mol-1
»¯Ñ§¼ü | C¡ªH | H¡ªH | H¡ªO |
¼üÄÜkJ/mol | b | c | d |
(1)д³ö¼×ÍéµÄ½á¹¹Ê½___________
(2)C=OµÄ¼üÄÜΪ_______________kJ/mol(Óú¬a¡¢b¡¢c¡¢dµÄʽ×Ó±íʾ)
(3)ºãÎÂÌõ¼þÏ£¬ÔÚÌå»ýºãΪ0.5LµÄÃܱÕÈÝÆ÷ÖÐͨÈëÒ»¶¨Á¿¼×ÍéºÍË®ÕôÆø£¬·¢ÉúÉÏÊö·´Ó¦¡£²âµÃ¼×ÍéÎïÖʵÄÁ¿Ëæʱ¼ä±ä»¯ÈçϱíËùʾ¡£0¡«10minÄÚÓÃH2OµÄŨ¶È±íʾ¸Ã·´Ó¦µÄƽ¾ùËÙÂÊΪ¦Ô(H2O)=_____________
ʱ¼ä/min | 0 | 10 | 20 | 40 | 50 | 60 |
n(CH4)/mol | 0.50 | 0.35 | 0.25 | 0.10 | 0.10 | 0.10 |
(4)ºãκãÈÝÇé¿öÏ£¬ÏÂÁÐÐðÊöÄÜ˵Ã÷´Ë·´Ó¦´ïµ½Æ½ºâ״̬µÄÊÇ_______________¡£
a£®»ìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿±£³Ö²»±äb£®CO2ºÍH2µÄÌå»ý·ÖÊý±ÈΪ1©s4
c£®»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±äd£®1molCO2Éú³ÉµÄͬʱÓÐ4molH-H¼ü¶ÏÁÑ
(5)д³ö¼×ÍéȼÁϵç³Ø£¬ÒÔKOHÈÜҺΪ½éÖÊʱ£¬¸º¼«µÄµç¼«·´Ó¦Ê½______
¡¾´ð°¸¡¿ 2b+2d-2c-
0.06molL1min1 ad 10OH£+CH4£8e£=
+7H2O
¡¾½âÎö¡¿
(1)¼×ÍéµÄ·Ö×ÓʽΪCH4£¬¼×ÍéΪÕýËÄÃæÌå½á¹¹£¬½á¹¹Ê½Îª£º£¬
¹Ê´ð°¸Îª£º£»
(2)¸ù¾Ý¦¤H=·´Ó¦ÎïµÄ¼üÄÜ×ܺÍ-Éú³ÉÎïµÄ¼üÄÜ×ܺͼÆË㣬¦¤H3=4b+4d-2E(C=O)-4c=a£¬½âµÃ£ºE(C=O)= 2b+2d-2c-£¬
¹Ê´ð°¸Îª£º2b+2d-2c-£»
(3) 0¡«10minÄÚ¼×ÍéµÄ·´Ó¦ÎïÖʵÄÁ¿±ä»¯Á¿Îª£º0.50 mol -0.35 mol =0.15mol£¬£¬¸ù¾ÝËÙÂÊÖ®±ÈµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È£¬¿ÉµÃ¦Ô(H2O)=
£¬
¹Ê´ð°¸Îª£º0.06molL1min1£»
(4) a£®·´Ó¦Ç°ºóÆøÌåµÄ×ÜÖÊÁ¿²»±ä£¬ÆøÌåµÄÎïÖʵÄÁ¿Ôö¼Ó£¬Ôò·´Ó¦¹ý³ÌÖлìºÏÆøÌåµÄƽ¾ùÏà¶Ô·Ö×ÓÖÊÁ¿ÊDZäÁ¿£¬µ±Æä±£³Ö²»±äʱ·´Ó¦´ïµ½Æ½ºâ״̬£¬¹Êa¿É˵Ã÷·´Ó¦´ïµ½Æ½ºâ״̬£»
b£®CO2ºÍH2¾ùΪ²úÎ·´Ó¦¹ý³ÌÖÐÁ½ÕßµÄÎïÖʵÄÁ¿Ö®±ÈʼÖÕµÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È£¬Ìå»ý·ÖÊý±ÈΪ1©s4²»±ä£¬¹Êb²»¿É˵Ã÷¸Ã·´Ó¦´ïµ½Æ½ºâ״̬£»
c£®·´Ó¦¹ý³ÌÖÐÆøÌåÖÊÁ¿²»±ä£¬ÈÝÆ÷Ìå»ý²»±ä£¬ÔòÆøÌåµÄÃܶÈʼÖÕ±£³Öºã¶¨£¬Òò´Ë»ìºÏÆøÌåµÄÃܶȱ£³Ö²»±ä²»ÄÜ˵Ã÷·´Ó¦´ïµ½Æ½ºâ״̬£»
d£®1molCO2Éú³ÉÊÇÕýÏò·´Ó¦£¬Í¬Ê±ÓÐ4molH-H¼ü¶ÏÁÑÊÇÄæÏò·´Ó¦£¬ÇÒËÙÂʱȵÈÓÚ»¯Ñ§¼ÆÁ¿ÊýÖ®±È£¬¿É˵Ã÷·´Ó¦´ïµ½Æ½ºâ״̬£»
¹Ê´ð°¸Îª£ºad£»
(5)¼×ÍéȼÁϵç³Ø¸º¼«ÊǼ×Í鷴Ӧת±ä³É¶þÑõ»¯Ì¼£¬ÔÚ¼îÐÔÌõ¼þ×îÖÕת±ä³É̼Ëá¸ùÀë×Ó£¬¸º¼«·´Ó¦Ê½Îª£º10OH£+CH4£8e£=+7H2O£¬
¹Ê´ð°¸Îª£º10OH£+CH4£8e£=+7H2O£»
![](http://thumb2018.1010pic.com/images/loading.gif)