ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿[2016¡¤½­ËÕ]ͨ¹ýÒÔÏ·´Ó¦¾ù¿É»ñÈ¡H2¡£ÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ

¢ÙÌ«Ñô¹â´ß»¯·Ö½âË®ÖÆÇ⣺2H2O(l)2H2(g)+O2(g) ¦¤H1=571.6 kJ¡¤mol1

¢Ú½¹Ì¿ÓëË®·´Ó¦ÖÆÇ⣺C(s)+H2O(g)CO(g)+H2(g) ¦¤H2=131.3 kJ¡¤mol1

¢Û¼×ÍéÓëË®·´Ó¦ÖÆÇ⣺CH4(g)+H2O(g)CO(g)+3H2(g) ¦¤H3=206.1 kJ¡¤mol1

A£®·´Ó¦¢ÙÖеçÄÜת»¯Îª»¯Ñ§ÄÜ

B£®·´Ó¦¢ÚΪ·ÅÈÈ·´Ó¦

C£®·´Ó¦¢ÛʹÓô߻¯¼Á£¬¦¤H3¼õС

D£®·´Ó¦CH4(g)C(s)+2H2(g)µÄ¦¤H=74.8 kJ¡¤mol1

¡¾´ð°¸¡¿D

¡¾½âÎö¡¿±¾Ì⿼²éÈÈ»¯Ñ§ÖªÊ¶£¬ÒâÔÚ¿¼²é¿¼Éú¶ÔÄÜÁ¿×ª»¯µÄÈÏʶÒÔ¼°¶Ô¸Ç˹¶¨ÂɵÄÕÆÎճ̶ȡ£AÏ·´Ó¦¢ÙÊǹâÄÜת»¯Îª»¯Ñ§ÄÜ£¬´íÎó£»BÏ·´Ó¦¢ÚµÄìʱäΪÕýÖµ£¬ÊôÓÚÎüÈÈ·´Ó¦£¬´íÎó£»CÏ´ß»¯¼Á²»»á¸Ä±ä·´Ó¦µÄìʱ䣬´íÎó£»DÏ¸ù¾Ý¸Ç˹¶¨ÂÉ£¬¢Û¢ÚµÃËùÇó·´Ó¦£¬ÆäìʱäΪ£º206.1 kJ¡¤mol1131.3 kJ¡¤mol1=74.8 kJ¡¤mol1£¬ÕýÈ·¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿£¨12·Ö£©

SCRºÍNSR¼¼Êõ¿ÉÓÐЧ½µµÍ²ñÓÍ·¢¶¯»úÔÚ¿ÕÆø¹ýÁ¿Ìõ¼þϵÄNOxÅÅ·Å¡£

£¨1£©SCR£¨Ñ¡ÔñÐÔ´ß»¯»¹Ô­£©¹¤×÷Ô­Àí£º

¢Ù ÄòËØ[CO(NH2)2]Ë®ÈÜÒºÈÈ·Ö½âΪNH3ºÍCO2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º____________¡£

¢Ú ·´Ó¦Æ÷ÖÐNH3»¹Ô­CO2µÄ»¯Ñ§·½³Ìʽ£º____________¡£

¢Û µ±È¼ÓÍÖк¬ÁòÁ¿½Ï¸ßʱ£¬Î²ÆøÖÐSO2ÔÚO2×÷ÓÃÏ»áÐγÉ(NH4)2SO4£¬Ê¹´ß»¯¼ÁÖж¾¡£Óû¯Ñ§·½³Ìʽ±íʾ(NH4)2SO4µÄÐγɣº________¡£

¢Ü ÄòËØÈÜҺŨ¶ÈÓ°ÏìNO2µÄת»¯£¬²â¶¨ÈÜÒºÖÐÄòËØ£¨M=60 mg¡¤L1£©º¬Á¿µÄ·½·¨ÈçÏ£ºÈ¡a gÄòËØÈÜÒº£¬½«Ëùº¬µªÍêȫת»¯ÎªNH3£¬ËùµÃNH3ÓùýÁ¿µÄv1 mL c1 mol¡¤L1 H2SO4ÈÜÒºÎüÊÕÍêÈ«£¬Ê£ÓàH2SO4ÓÃv2 mL c2 mol¡¤L1 NaOHÈÜҺǡºÃÖкͣ¬ÔòÄòËØÈÜÒºÖÐÈÜÖʵÄÖÊÁ¿·ÖÊýÊÇ_________¡£

£¨2£©NSR£¨NOx´¢´æ»¹Ô­£©¹¤×÷Ô­Àí£º

NOxµÄ´¢´æºÍ»¹Ô­ÔÚ²»Í¬Ê±¶Î½»Ìæ½øÐУ¬ÈçͼaËùʾ¡£

¢Ù ͨ¹ýBaOºÍBa(NO3)2µÄÏ໥ת»¯ÊµÑéNOxµÄ´¢´æºÍ»¹Ô­¡£´¢´æNOxµÄÎïÖÊÊÇ_________¡£

¢Ú ÓÃH2Ä£ÄâβÆøÖл¹Ô­ÐÔÆøÌåÑо¿ÁËBa(NO3)2µÄ´ß»¯»¹Ô­¹ý³Ì£¬¸Ã¹ý³Ì·ÖÁ½²½½øÐУ¬Í¼b±íʾ¸Ã¹ý³ÌÏà¹ØÎïÖÊŨ¶ÈËæʱ¼äµÄ±ä»¯¹Øϵ¡£µÚÒ»²½·´Ó¦ÏûºÄµÄH2ÓëBa(NO3)2µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ__________¡£

¢Û »¹Ô­¹ý³ÌÖУ¬ÓÐʱ»á²úÉúЦÆø£¨N2O£©¡£ÓÃͬλËØʾ×Ù·¨Ñо¿·¢ÏÖЦÆøµÄ²úÉúÓëNOÓйء£ÔÚÓÐÑõÌõ¼þÏÂ15NOÓëNH3ÒÔÒ»¶¨±ÈÀý·´Ó¦Ê±£¬µÃµ½µÄЦÆø¼¸ºõ¶¼ÊÇ15NNO¡£½«¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ²¹³äÍêÕû£º_______¡õ15NNO+¡õH2O

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø