ÌâÄ¿ÄÚÈÝ

Óм¸ÖÖÔªËصÄ΢Á£µÄºËÍâµç×Ó²ã½á¹¹ÈçͼËùʾ¡£

Çë»Ø´ðÏÂÁÐÎÊÌâ¡£
£¨1£©Èô¸Ã΢Á£ÊÇÖÐÐÔ΢Á££¬ÕâÖÖ΢Á£µÄ·ûºÅÊÇ_____________¡£
£¨2£©Èô¸Ã΢Á£µÄÑÎÈÜÒºÄÜʹäåË®ÍËÉ«£¬²¢³öÏÖ»ë×Ç£¬ÕâÖÖ΢Á£µÄ·ûºÅÊÇ____________¡£
£¨3£©Èô¸Ã΢Á£µÄÑõ»¯ÐÔºÜÈõ£¬µÃµ½1¸öµç×Óºó±äΪԭ×Ó£¬Æäµ¥ÖʵĻ¹Ô­ÐÔºÜÇ¿£¬ÕâÖÖ΢Á£µÄ·ûºÅÊÇ________________¡£
£¨4£©Èô¸Ã΢Á£µÄ»¹Ô­ÐÔºÜÈõ£¬Ê§È¥1¸öµç×Óºó±äΪԭ×Ó£¬Æäµ¥ÖʵÄÑõ»¯ÐÔºÜÇ¿£¬ÕâÖÖ΢Á£µÄ·ûºÅÊÇ_______________

£¨1£©Ar £¨2£©S2£­ £¨3£© K£«  (4) Cl£­

½âÎöÊÔÌâ·ÖÎö£º£¨1£©Èô¸Ã΢Á£ÊÇÖÐÐÔ΢Á££¬ÔòÖÊ×ÓÊý£½ºËÍâµç×ÓÊý£½2+8+8£½18£¬Òò´ËÕâÖÖ΢Á£µÄ·ûºÅÊÇAr¡£
£¨2£©Èô¸Ã΢Á£µÄÑÎÈÜÒºÄÜʹäåË®ÍËÉ«£¬²¢³öÏÖ»ë×Ç£¬ËµÃ÷¸Ã΢Á£¾ßÓл¹Ô­ÐÔ£¬ËùÒÔÕâÖÖ΢Á£µÄ·ûºÅÊÇS2£­¡£
£¨3£©Èô¸Ã΢Á£µÄÑõ»¯ÐÔºÜÈõ£¬µÃµ½1¸öµç×Óºó±äΪԭ×Ó£¬Æäµ¥ÖʵĻ¹Ô­ÐÔºÜÇ¿£¬Òò´ËÓ¦¸ÃÊÇ»îÆõļî½ðÊô£¬ÖÊ×ÓÊý£½2+8+8+1£½19£¬ËùÒÔÕâÖÖ΢Á£µÄ·ûºÅÊÇK£«¡£
£¨4£©Èô¸Ã΢Á£µÄ»¹Ô­ÐÔºÜÈõ£¬Ê§È¥1¸öµç×Óºó±äΪԭ×Ó£¬Æäµ¥ÖʵÄÑõ»¯ÐÔºÜÇ¿£¬Ôò¸Ã΢Á£µÄÖÊ×ÓÊýÕâÖÖ΢Á£µÄ·ûºÅÊÇ2+8+8£­1£½17£¬ËùÒÔÕâÖÖ΢Á£µÄ·ûºÅÊÇCl£­¡£
¿¼µã£º¿¼²éºËÍâµç×ÓÅŲ¼¡¢Ñõ»¯ÐԺͻ¹Ô­ÐÔ¡¢ºËÍâµç×ÓÊýÓëÖÊ×ÓÊý¹ØϵµÄÅжϵÈ
µãÆÀ£º¸ÃÌâÉè¼ÆÐÂÓ±£¬»ù´¡ÐÔÇ¿£¬²àÖضÔѧÉú½âÌâÄÜÁ¦µÄÅàÑø£¬ÓÐÀûÓÚÅàÑøѧÉúµÄÂß¼­ÍÆÀíÄÜÁ¦ºÍ·¢É¢Ë¼Î¬ÄÜÁ¦¡£Ã÷ȷ΢Á£µÄºËÍâµç×ÓÊýÓëÖÊ×ÓÊýµÄ¹ØϵÊÇ´ðÌâµÄ¹Ø¼ü¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ÓйضÌÖÜÆÚÔªËØA¡¢B¡¢C¡¢D¡¢E¡¢FµÄÐÅÏ¢ÈçÏ£º

ÔªËØ
ÓйØÐÅÏ¢
A
×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯Î¼×£©ÄÜÓëÆäÆø̬Ç⻯ÎÒÒ£©·´Ó¦Éú³ÉÑÎ
B
×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ2±¶
C
M²ãÉÏÓÐ3¸öµç×Ó
D
¶ÌÖÜÆÚÔ­×Ӱ뾶×î´óµÄÖ÷×åÔªËØ
E
Æäµ¥ÖÊÊǵ­»ÆÉ«¹ÌÌå
F
×î¸ßÕý¼ÛÓë×îµÍ¸º¼Û´úÊýºÍΪ6
 
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öʵÑéÊÒÖÆÈ¡ÒҵĻ¯Ñ§·½³Ìʽ                                                   ¡£
£¨2£©ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ                (ÌîÐòºÅ)¡£
¢ÙʵÑéÊÒ¿ÉÓÃÈçͼËùʾװÖÃÖÆÈ¡BµÄ×î¸ß¼ÛÑõ»¯Îï

¢ÚÓÃCµ¥ÖÊ×ö³ÉµÄ²Û³µ£¬¶¼¿ÉÓÃÀ´ÔËÊä¼×µÄŨÈÜÒº
¢Û CºÍÍ­ÓëÏ¡ÁòËá×é³ÉµÄÔ­µç³Ø£¬Cµç¼«±»»¹Ô­
¢Ü Dµ¥ÖÊÔÚÑõÆøÖÐȼÉÕºóµÄ²úÎï¿ÉÓÃÔÚ·À¶¾Ãæ¾ßÖÐ×÷¹©Ñõ¼Á
¢Ý¹ÄÀø³Ë×ø¹«½»³µ³öÐУ¬³«µ¼µÍ̼Éú»î£¬ÊÇ¿ØÖƺÍÖÎÀíBO2½â¾ö¡°ÎÂÊÒЧӦ¡±µÄÓÐЧ;¾¶Ö®Ò»
¢Þ DFµÄµç×ÓʽΪH¡ÃCl¡Ã
£¨3£©½«EµÄ³£¼ûÑõ»¯Î¸ÃÑõ»¯ÎïÄÜʹƷºìÈÜÒºÍÊÉ«£©Í¨ÈëÓÉCuSO4ºÍNaCl»ìºÏµÄŨÈÜÒºÖУ¬ÈÜÒºÑÕÉ«±ädz£¬Îö³ö°×É«³Áµí£¬È¡¸Ã³Áµí½øÐÐÔªËØÖÊÁ¿·ÖÊý·ÖÎö£¬¿ÉÖªÆäÖк¬Cl£º35.7%£¬Cu£º64.3%£¬Ôò¸ÃÑõ»¯ÎïÔÚÉÏÊö·´Ó¦ÖеÄ×÷ÓÃÊÇ             ¡£
A£®Æ¯°×¼Á                 B£®Ñõ»¯¼Á             C£®»¹Ô­¼Á
£¨4£©ÇëÓû¯Ñ§·½·¨¼ÓÒÔÑéÖ¤£¨3£©ÖеÄÑõ»¯Î¼òҪд³öʵÑé·½·¨¡¢ÊÔ¼Á¼°Ô¤Æڿɹ۲쵽µÄÏÖÏó     ¡£

ÏÖÓÐÎåÖÖ¶ÌÖÜÆÚÖ÷×åÔªËØA¡¢B¡¢C¡¢   D¡¢E£¬ÆäÔ­×ÓÐòÊýÒÀ´ÎÔö´ó¡£AÔ­×ÓÔ¼Õ¼ÓîÖæÖÐÔ­×Ó×ÜÊýµÄ88.6%£¬A+ÓÖ³ÆΪÖÊ×Ó£ºBÊÇÐγɻ¯ºÏÎïÖÖÀà×î¶àµÄÔªËØ£¬CÔªËصÄ×î¼òµ¥µÄÇ⻯ÎïYµÄË®ÈÜÒºÏÔ¼îÐÔ£®EÊǶÌÖÜÆÚÔªËØÖе縺ÐÔ×îСµÄÔªËØ¡£A¡¢B¡¢C¡¢EËÄÖÖÔªËض¼ÄÜÓëDÔªËØÐγÉÔ­×Ó¸öÊý±È²»ÏàͬµÄ³£¼û»¯ºÏÎï¡£ÊԻشðÏÂÁÐÎÊÌ⣺
£¨1£©Ð´³öA¡¢EÁ½ÔªËØÐγɵÄÔ­×Ó¸öÊý±ÈΪ1:1µÄ»¯ºÏÎïµÄµç×Óʽ____¡£
£¨2£©ÏòÂÈ»¯ÑÇÌúÈÜÒºµÎ¼Ó¹ýÁ¿µÄEµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïµÄÈÜÒº£¬ÏÖÏóÊÇ____¡£
£¨3£©YÈÜÒºÏÔ¼îÐÔµÄÔ­ÒòÊÇ(ÓÃÒ»¸öÀë×Ó·½³Ìʽ±íʾ£©____¡£
£¨4£©¼ìÑéÆû³µÎ²ÆøÖк¬ÓеĻ¯ºÏÎïBDµÄ·½·¨ÊÇ£ºÏòËáÐÔPdC12ÈÜÒºÖÐͨAÆû³µÎ²Æø£¬ÈôÉú³ÉºÚÉ«³Áµí£¨Pd£©£¬Ö¤Ã÷Æû³µÎ²ÆøÖк¬ÓÐBD¡£Ð´³ö·´Ó¦µÄÀë×Ó·½³Ìʽ____¡£
£¨5£©ÏÂÁÐÓйØÎïÖÊÐÔÖʵıȽÏÖУ®²»ÕýÈ·µÄÊÇ               ¡£
a£®ÈÈÎȶ¨ÐÔ£ºH2S>SiH4  b£®Àë×Ӱ뾶£ºNa+>S2£­
c£®µÚÒ»µçÀëÄÜN>O   d£®ÔªËص縺ÐÔ£ºC>H
£¨6£©ÒÑÖª£º¢ÙCH3OH(g)+H2O(g)=CO2(g)+3H2(g)  ¡÷H=+49.0kJ/mol
¢ÚCH3OH(g)+3/2O2(g)=CO2(g)+2H2O(g)  ¡÷H=£­192£®9kJ/mol
ÓÉÉÏÊö·½³Ìʽ¿ÉÖª£®CH3OHµÄȼÉÕÈÈ____£¨Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»òСÓÚ¡±£©192.9kJ/mol¡£ÒÑ֪ˮµÄÆø»¯ÈÈΪ44 kJ/mol£®Ôò±íʾÇâÆøȼÉÕÈȵÄÈÈ»¯Ñ§·½³ÌʽΪ____¡£

ÒÑÖªA¡¢B¡¢CÊǵڶþÖÜÆڵķǽðÊôÔªËØ£¬ÆäÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÇÒËüÃÇÖ®¼ä¿ÉÒÔÐγÉACºÍBCÒÔ¼°AC2ºÍBC2·Ö×Ó£¬DÔªËØÊÇÒ»ÖÖ¶ÌÖÜÆÚÔªËØ£¬ËüÓëA¡¢B¡¢C¿É·Ö±ðÐγɵç×Ó×ÜÊýÏàµÈµÄÈýÖÖ·Ö×Ó¡£ÇëÌî¿Õ£º
(1)д³öA¡¢B¡¢C¡¢D¶ÔÓ¦µÄÔªËØ·ûºÅ£ºA________¡¢B________¡¢C________¡¢D________¡£
(2)д³ö¹¤ÒµÉú²úÖÐBD3ÓëÑõÆø·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
________________________________________________________________________¡£
(3)ÄãÈÏΪB¡¢C¡¢DÔªËØÐγɵĻ¯ºÏÎïÖ®¼ä________(Ìî¡°ÄÜ¡±»ò¡°²»ÄÜ¡±)·¢ÉúÏÂÃæµÄ·´Ó¦BC£«BD3¨D¡úDBC2£«D2C£¬µÃ³öÉÏÃæ½áÂÛµÄÀíÓÉÊÇ__________________________ _¡£
(4)¢ñ.ºãκãѹÏ£¬ÔÚÒ»Ìå»ý¿É±äµÄÃܱÕÈÝÆ÷Öз¢ÉúÏÂÁз´Ó¦£º4AC(g)£«2BC2(g) 4AC2(g)£«B2(g)ÔÚÉÏÊöÌõ¼þÏ£¬ÏòÈÝÆ÷ÖгäÈëACºÍBC2¸÷1 mol´ïƽºâʱ£¬Éú³ÉAC2ºÍB2¹²a mol£¬ÔòACµÄת»¯ÂÊÊÇ________(Óú¬aµÄ´úÊýʽ±íʾ)¡£
¢ò. Èôά³ÖζȲ»±ä£¬ÔÚÒ»¸öÓë¢ñ·´Ó¦Ç°µÄÆðʼÌå»ýÏàͬ£¬ÈÝ»ý¹Ì¶¨µÄÃܱÕÈÝÆ÷Öз¢Éú¢ñÖÐËùÊöµÄ»¯Ñ§·´Ó¦£¬¿ªÊ¼Ê±ÈÔÏòÈÝÆ÷ÖгäÈëACºÍBC2¸÷1 mol£¬´ïƽºâʱÉú³ÉAC2ºÍB2¹²b mol£¬½«bÓë¢ñÖеÄa½øÐбȽϣ¬Ôòa________b(Ìî¡°£¾¡±¡°£¼¡±¡°£½¡±»ò¡°²»ÄÜÈ·¶¨¡±)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø