ÌâÄ¿ÄÚÈÝ
7£®A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖ¶ÌÖÜÆÚÔªËصÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬ÒÑÖª£º¢ÙAÔ×Ӱ뾶×îС£»¢ÚBÔ×Ó×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ2±¶£»¢ÛCÔ×Ó×îÍâ²ãµç×ÓÊý±È´ÎÍâ²ãµç×ÓÊý¶à4¸ö£»¢ÜDÔ×ӵĴÎÍâ²ãµç×ÓÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ8±¶£»¢ÝEµ¥ÖʼÈÄܺÍÑÎËá·´Ó¦ÓÖÄܺÍÉռӦ£»¢ÞFÓëCͬÖ÷×壮»Ø´ðÏÂÁÐÎÊî}£º£¨1£© ÔÚÁùÖÖÔªËØÖУ¬ÐγÉÎïÖÊÖÖÀà×î¶àµÄÊÇ̼£¨ÌîÔªËØÃû³Æ£©£»
£¨2£© д³öCÔªËØËùÓеÄÇ⻯ÎïµÄµç×Óʽ¡¢£»
£¨3£© Óõç×Óʽ±íʾD2F•µÄÐγɹý³Ì£»
£¨4£© д³öEÓëÉÕ¼îÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ2Al+2OH-+2H2O=2AlO2-+3H2¡ü£®
·ÖÎö A¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖ¶ÌÖÜÆÚÔªËصÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬¢ÙAÔ×Ӱ뾶×îС£¬ÔòAΪHÔªËØ£»¢ÚBÔ×Ó×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ2±¶£¬×îÍâ²ãµç×ÓÊý²»³¬¹ý8¸ö£¬Ô×ÓÖ»ÄÜÓÐ2¸öµç×Ӳ㣬×îÍâ²ãµç×ÓÊýΪ4£¬¹ÊBΪ̼ԪËØ£»¢ÛCÔ×Ó×îÍâ²ãµç×ÓÊý±È´ÎÍâ²ãµç×ÓÊý¶à4¸ö£¬×îÍâ²ãµç×ÓÊý²»³¬¹ý8¸ö£¬Ô×ÓÖ»ÄÜÓÐ2¸öµç×Ӳ㣬×îÍâ²ãµç×ÓÊýΪ6£¬¹ÊCΪOÔªËØ£»¢ÜDÔ×ӵĴÎÍâ²ãµç×ÓÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ8±¶£¬×îÍâ²ãµç×ÓÊýÖ»ÄÜΪ1£¬ÔòDΪNa£»¢ÝEµ¥ÖʼÈÄܺÍÑÎËá·´Ó¦ÓÖÄܺÍÉռӦ£¬ÔòEΪAl£»¢ÞFÓëCͬÖ÷×壬ÔòFΪSÔªËØ£¬¾Ý´Ë½â´ð£®
½â´ð ½â£ºA¡¢B¡¢C¡¢D¡¢E¡¢FÁùÖÖ¶ÌÖÜÆÚÔªËصÄÔ×ÓÐòÊýÒÀ´ÎÔö´ó£¬¢ÙAÔ×Ӱ뾶×îС£¬ÔòAΪHÔªËØ£»¢ÚBÔ×Ó×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ2±¶£¬×îÍâ²ãµç×ÓÊý²»³¬¹ý8¸ö£¬Ô×ÓÖ»ÄÜÓÐ2¸öµç×Ӳ㣬×îÍâ²ãµç×ÓÊýΪ4£¬¹ÊBΪ̼ԪËØ£»¢ÛCÔ×Ó×îÍâ²ãµç×ÓÊý±È´ÎÍâ²ãµç×ÓÊý¶à4¸ö£¬×îÍâ²ãµç×ÓÊý²»³¬¹ý8¸ö£¬Ô×ÓÖ»ÄÜÓÐ2¸öµç×Ӳ㣬×îÍâ²ãµç×ÓÊýΪ6£¬¹ÊCΪOÔªËØ£»¢ÜDÔ×ӵĴÎÍâ²ãµç×ÓÊýÊÇ×îÍâ²ãµç×ÓÊýµÄ8±¶£¬×îÍâ²ãµç×ÓÊýÖ»ÄÜΪ1£¬ÔòDΪNa£»¢ÝEµ¥ÖʼÈÄܺÍÑÎËá·´Ó¦ÓÖÄܺÍÉռӦ£¬ÔòEΪAl£»¢ÞFÓëCͬÖ÷×壬ÔòFΪSÔªËØ£®
£¨1£©ÔÚÁùÖÖÔªËØÖУ¬Ì¼ÔªËØÐγÉÓлúÎÐγÉÎïÖÊÖÖÀà×î¶à£¬¹Ê´ð°¸Îª£ºÌ¼£»
£¨2£©CÔªËصÄÇ⻯ÎïÓÉH2O¡¢H2O2£¬µç×Óʽ·Ö±ðΪ¡¢£¬¹Ê´ð°¸Îª£º£»£»
£¨3£©Óõç×Óʽ±íʾNa2SµÄÐγɹý³ÌΪ£º£¬
¹Ê´ð°¸Îª£º£»
£¨4£©AlÓëÉÕ¼îÈÜÒº·´Ó¦µÄÀë×Ó·½³Ìʽ£º2Al+2OH-+2H2O=2AlO2-+3H2¡ü£¬¹Ê´ð°¸Îª£º2Al+2OH-+2H2O=2AlO2-+3H2¡ü£®
µãÆÀ ±¾Ì⿼²é½á¹¹ÐÔÖÊλÖùØϵ×ÛºÏÓ¦Óã¬ÍƶÏÔªËØÊǽâÌâ¹Ø¼ü£¬²àÖضԻ¯Ñ§ÓÃÓïµÄ¿¼²é£¬×¢ÒâÕÆÎÕÓõç×Óʽ±íʾÎïÖÊ»ò»¯Ñ§¼üµÄÐγɣ¬ÄѶÈÖеȣ®
A£® | µí·ÛÓëÏËάËØ»¥ÎªÍ¬·ÖÒì¹¹Ìå | |
B£® | ¹¤ÒµÉÏÒÔʯÓÍΪÔÁÏÉú²úÒÒÏ© | |
C£® | ÓÍÖ¬²»ÊÇõ¥ | |
D£® | ³ä·ÖȼÉÕºóÖ»Éú³ÉCO2ºÍH2OµÄÓлúÎï¾ÍÊÇÌþ |
A£® | ·Ö×Ó¾§ÌåÖж¼´æÔÚ¹²¼Û¼ü | B£® | ÔÚµ¥Öʵľ§ÌåÖÐÒ»¶¨²»´æÔÚÒõÀë×Ó | ||
C£® | Àë×Ó¾§ÌåÖÐÖ»ÓÐÀë×Ó¼ü | D£® | ¸É±ùºÍ±ùÖÐ×÷ÓÃÁ¦ÍêÈ«Ïàͬ |
A£® | c£¨OH-£©=c£¨H+£©+c£¨HS-£©+c£¨H2S£© | |
B£® | ÈÜÒºÖи÷Àë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòΪ£ºc£¨Na+£©£¾c£¨OH-£©£¾c£¨HS-£©£¾c£¨S2-£©£¾c£¨H+£© | |
C£® | 2 c£¨Na+£©=c£¨S2-£©+c£¨HS-£©+c£¨H2S£© | |
D£® | ÅäÖÆ0.1mol•L-1µÄNa2SÈÜҺʱÐè¼ÓÉÙÁ¿µÄKOHÒÖÖÆS2-µÄË®½â |
A£® | Ô×Ó×îÍâ²ãµç×ÓÊý£ºX£¾Y£¾Z | B£® | Á£×Ӱ뾶£ºr£¨W3+£©£¾r£¨Y2-£©£¾r£¨Z+£© | ||
C£® | MY2ÓëZ2YµÄ»¯ºÏÎïÀàÐÍÏàͬ | D£® | µ¥Öʷе㣺M£¾Z£¾Y |
A£® | ¹ýÁ¿HIÈÜÒº¼ÓÈëµ½Fe£¨NO3£©3ÈÜÒºÖУº2Fe3++2I-¨T2Fe2++I2 | |
B£® | º¬µÈÎïÖʵÄÁ¿µÄMgCl2¡¢Ba£¨OH£©2¡¢HNO3ÈýÖÖÈÜÒº»ìºÏ£ºMg2++2OH-¨TMg£¨OH£©2¡ý | |
C£® | CaCO3ÈÜÓÚ´×Ë᣺CaCO3+2CH3COOH¨TCa2++2CH3COO-+CO2¡ü+2H2O | |
D£® | Ïòº£´ø»Ò½þ³öÒºÖмÓÈëÁòËᡢ˫ÑõË®£º2I-+H2O2¨T2OH-+I2 |