ÌâÄ¿ÄÚÈÝ

10£®£¨1£©ÏÂÁи÷×éÖеÄÁ½ÖÖ¹Ì̬ÎïÖÊÈÛ»¯£¨»òÉý»ª£©Ê±£¬¿Ë·þµÄ΢Á£¼äÏ໥×÷ÓÃÁ¦ÊôÓÚͬÖÖÀàÐ͵ÄÊÇC£¨Ñ¡ÌîA¡¢B¡¢C¡¢D£©£®
A  µâºÍµâ»¯ÄÆ                            B  ½ð¸ÕʯºÍÖؾ§Ê¯
C  ±ù´×ËáºÍÓ²Ö¬Ëá¸ÊÓÍõ¥                   D  ¸É±ùºÍ¶þÑõ»¯¹è
£¨2£©µÈÌå»ý£¨V£©»ìºÏÒÒËáºÍ±½£¬»ìºÏÈÜÒºµÄÌå»ý´óÓÚ2V£¨Ì´óÓÚ¡¢µÈÓÚ¡¢Ð¡ÓÚ¡¢²»È·¶¨£©
£¨3£©Áª°±£¨N2H4£©Óë°±ÏàËÆ£¬Ð´³öÁª°±µÄ½á¹¹Ê½ ÆäÖÐNµÄÔÓ»¯¹ìµÀÊÇsp3£»Áª°±Ò²ÓмîÐÔ£¬Æä¼îÐÔÈõÓÚ°± £¨ÌǿÓÚ¡¢ÈõÓÚ£©£»Áª°±µÄÎȶ¨ÐÔÈõÓÚ°±£¨ÌǿÓÚ¡¢ÈõÓÚ£©
£¨4£©ÂÈ»¯Äƾ§°ûÖУ¬ÄÆÀë×ÓÖ®¼ä×î¶Ì¾àÀëΪa cm£¬ÃܶÈΪb g/cm3£¬ÆäĦ¶ûÖÊÁ¿ÎªM g/mol£¬ÔòNA=$\frac{\sqrt{2}M}{2{a}^{3}b}$/mol £¨ÓÃM¡¢a¡¢b±íʾ£©
£¨5£©PF3¡¢NF3 ºÍNH3½á¹¹ÏàËÆ£¬¼ü½Ç´óС˳ÐòΪNH3£¾NF3£¾PF3£®

·ÖÎö £¨1£©¹Ì̬ÎïÖÊÈÛÈÚʱ£¬·Ö×Ó¾§Ìå¿Ë·þ·Ö×Ó¼ä×÷ÓÃÁ¦¡¢Ô­×Ó¾§Ìå¿Ë·þ»¯Ñ§¼ü¡¢Àë×Ó¾§Ìå¿Ë·þÀë×Ó¼ü¡¢½ðÊô¾§Ìå¿Ë·þ½ðÊô¼ü£»
£¨2£©±½·Ö×ÓÓë´×Ëá·Ö×ÓÖ®¼äµÄÎüÒýÁ¦£¬±È±½·Ö×Ó¼äµÄÎüÒýÁ¦ºÍ´×Ëá·Ö×Ó¼äµÄÎüÒýÁ¦¶¼ÒªÈõ£»
£¨3£©°±Æø·Ö×ÓÖеÄÒ»¸öHÔ­×Ó±»°±»ùÈ¡´úΪÁª°±£¬¾Ý´ËÊéдÁª°±½á¹¹Ê½£»¸Ã·Ö×ÓÖÐNÔ­×Ó¼Û²ãµç×Ó¶Ô¸öÊýÊÇ4ÇÒº¬ÓÐÒ»¸ö¹Âµç×Ó¶Ô£¬¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛÅжÏNÔ­×ÓÔÓ»¯·½Ê½£»
N2H4Ï൱ÓÚNH3µÄÒ»¸öHÔ­×Ó»»³ÉÁË-NH2£¬ÏÔÈ»NÔ­×ÓµÄÎüµç×ÓÄÜÁ¦Ô¶Ç¿ÓÚHÔ­×Ó£¬Òò´ËN2H4ÖеÄNÔ­×ÓÉϵç×ÓÔÆÃܶÈСÓÚNH3£¬¸üÄѽáºÏH+£¬¼îÐÔÈõ£®
¿ÉÒÔÀí½âΪH2N-Nµ¥¼üµÄ¹²Óõç×Ó¶Ô±ÈH2N-HµÄ¹²Óõç×Ó¶Ô¸üÔ¶Àë×ó±ßµÄN£»
·Ö×ÓÖУ¬¼üÄÜԽС¸Ã·Ö×ÓÔ½²»Îȶ¨£»
£¨4£©ÂÈ»¯Äƾ§°ûÖУ¬ÄÆÀë×ÓÖ®¼ä×î¶Ì¾àÀëΪa cm£¬Ôò¾§°ûÀⳤΪ$\sqrt{2}$acm£¬¾§°ûÌå»ý=£¨$\sqrt{2}$acm£©
3£¬¸Ã¾§°ûÖÐÄÆÀë×Ó¸öÊý=8¡Á$\frac{1}{8}$+6¡Á$\frac{1}{2}$=4£¬ÂÈÀë×Ó¸öÊý=12¡Á$\frac{1}{4}$+1=4£¬°¢·üÙ¤µÂÂÞ³£Êý=$\frac{4M}{¦ÑV}$£»   
£¨5£©PF3¡¢NF3 ºÍNH3½á¹¹ÏàËƵÄÊÇÈý½Ç׶Ðνṹ£¬Åäλԭ×ÓÏàͬʱ£¬ÖÐÐÄÔ­×ӵĵ縺ÐÔÔ½´ó£¬¼ü½ÇÔ½´ó£®

½â´ð ½â£º£¨1£©¹Ì̬ÎïÖÊÈÛÈÚʱ£¬·Ö×Ó¾§Ìå¿Ë·þ·Ö×Ó¼ä×÷ÓÃÁ¦¡¢Ô­×Ó¾§Ìå¿Ë·þ»¯Ñ§¼ü¡¢Àë×Ó¾§Ìå¿Ë·þÀë×Ó¼ü¡¢½ðÊô¾§Ìå¿Ë·þ½ðÊô¼ü£¬
A£®µâÊÇ·Ö×Ó¾§Ìå¡¢µâ»¯ÄÆÊÇÀë×Ó¾§Ì壬ÈÛÈÚʱ£¬Ç°ÕßÆÆ»µ·Ö×Ó¼ä×÷ÓÃÁ¦¡¢ºóÕßÆÆ»µÀë×Ó¼ü£¬ËùÒÔ¿Ë·þ΢Á£¼ä×÷ÓÃÁ¦²»Í¬£¬¹Ê²»Ñ¡£»                            
B£®½ð¸ÕʯÊÇÔ­×Ó¾§Ìå¡¢Öؾ§Ê¯ÊÇÀë×Ó¾§Ì壬ÈÛÈÚʱǰÕßÆÆ»µ»¯Ñ§¼ü¡¢ºóÕßÆÆ»µÀë×Ó¼ü£¬ËùÒÔ¿Ë·þ΢Á£¼ä×÷ÓÃÁ¦²»Í¬£¬¹Ê²»Ñ¡£»
C£®±ù´×ËáºÍÓ²Ö¬Ëá¸ÊÓÍõ¥¶¼ÊÇ·Ö×Ó¾§Ì壬ÈÛÈÚʱ¶¼ÊÇÆÆ»µ·Ö×Ó¼ä×÷ÓÃÁ¦£¬ËùÒÔÏàͬ£¬¹ÊÑ¡£»
D£®¸É±ùÊÇ·Ö×Ó¾§Ìå¡¢¶þÑõ»¯¹èÊÇÔ­×Ó¾§Ì壬ÈÛÈÚʱǰÕßÆÆ»µ·Ö×Ó¼ä×÷ÓÃÁ¦¡¢ºóÕßÆÆ»µ»¯Ñ§¼ü£¬ËùÒÔ¿Ë·þ΢Á£¼ä×÷ÓÃÁ¦²»Í¬£¬¹Ê²»Ñ¡£»
¹ÊÑ¡C£»
£¨2£©±½ºÍ±ù´×Ëá»ìºÏºó£¬±½·Ö×ÓÓë´×Ëá·Ö×ÓÖ®¼äµÄÎüÒýÁ¦£¬±È±½·Ö×Ó¼äµÄÎüÒýÁ¦ºÍ´×Ëá·Ö×Ó¼äµÄÎüÒýÁ¦¶¼ÒªÈõ£¬ËùÒÔ±½Óë±ù´×Ëá·Ö×Ó¼ä¾à¼Ó´ó£®´Ó¶øʹ×ÜÌå»ý´óÓÚÁ½ÈÜÒºÌå»ýÖ®ºÍ£¬¹Ê´ð°¸Îª£º´óÓÚ£»
£¨3£©°±Æø·Ö×ÓÖеÄÒ»¸öHÔ­×Ó±»°±»ùÈ¡´úΪÁª°±£¬Áª°±½á¹¹Ê½Îª£»¸Ã·Ö×ÓÖÐNÔ­×Ó¼Û²ãµç×Ó¶Ô¸öÊýÊÇ4ÇÒº¬ÓÐÒ»¸ö¹Âµç×Ó¶Ô£¬¸ù¾Ý¼Û²ãµç×Ó¶Ô»¥³âÀíÂÛµÃNÔ­×ÓÔÓ»¯·½Ê½Îªsp3£»
N2H4Ï൱ÓÚNH3µÄÒ»¸öHÔ­×Ó»»³ÉÁË-NH2£¬ÏÔÈ»NÔ­×ÓµÄÎüµç×ÓÄÜÁ¦Ô¶Ç¿ÓÚHÔ­×Ó£¬Òò´ËN2H4ÖеÄNÔ­×ÓÉϵç×ÓÔÆÃܶÈСÓÚNH3£¬¸üÄѽáºÏH+£¬¼îÐÔÈõ£»
¿ÉÒÔÀí½âΪH2N-Nµ¥¼üµÄ¹²Óõç×Ó¶Ô±ÈH2N-HµÄ¹²Óõç×Ó¶Ô¸üÔ¶Àë×ó±ßµÄN£»
¹Ê´ð°¸Îª£º£»sp3£»ÈõÓÚ£»ÈõÓÚ£»
£¨4£©ÂÈ»¯Äƾ§°ûÖУ¬ÄÆÀë×ÓÖ®¼ä×î¶Ì¾àÀëΪa cm£¬Ôò¾§°ûÀⳤΪ$\sqrt{2}$acm£¬¾§°ûÌå»ý=£¨$\sqrt{2}$acm£©3£¬¸Ã¾§°ûÖÐÄÆÀë×Ó¸öÊý=8¡Á$\frac{1}{8}$+6¡Á$\frac{1}{2}$=4£¬ÂÈÀë×Ó¸öÊý=12¡Á$\frac{1}{4}$+1=4£¬°¢·üÙ¤µÂÂÞ³£Êý=$\frac{4M}{¦ÑV}$=$\frac{4M}{£¨\sqrt{2}a£©^{3}b}$/mol=$\frac{\sqrt{2}M}{2{a}^{3}b}$/mol£¬
¹Ê´ð°¸Îª£º$\frac{\sqrt{2}M}{2{a}^{3}b}$/mol£»   
£¨5£©·Ö×ÓÖУ¬¼üÄÜԽС¸Ã·Ö×ÓÔ½²»Îȶ¨£¬NF3ºÍPF3µÄÅäλԭ×Ó¶¼ÊÇF£¬NµÄµç¸ºÐÔ´óÓÚP£¬ËùÒÔNF3µÄ¼ü½Ç´óÓÚPF3£¬NF3ºÍNH3µÄÖÐÐÄÔ­×ÓÏàͬ£¬FµÄµç¸ºÐÔ´óÓÚH£¬ËùÒÔNF3µÄ¼ü½ÇСÓÚNH3£¬Òò´Ë¼ü½ÇNH3£¾NF3£¾PF3£¬¹Ê´ð°¸Îª£ºNH3£¾NF3£¾PF3£®

µãÆÀ ±¾Ì⿼²éÎïÖʽṹºÍÐÔÖÊ£¬²àÖØ¿¼²éѧÉú¿Õ¼äÏëÏóÄÜÁ¦¼°¼ÆËãÄÜÁ¦£¬É漰΢Á£¼ä×÷ÓÃÁ¦¡¢¾§°û¼ÆËã¡¢¼ü½ÇµÈ֪ʶµã£¬ÄѵãÊǾ§°û¼ÆË㣬Ò×´íµãÊÇ£¨2£©Ì⣬ÌâÄ¿ÄѶÈÖеȣ®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø