ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿º£ÑóÖÐÓзḻµÄʳƷ¡¢¿ó²ú¡¢ÄÜÔ´¡¢Ò©ÎïºÍË®²ú×ÊÔ´µÈ(ÈçͼËùʾ)£¬
ÏÂÁÐÓйØ˵·¨ÕýÈ·µÄÊÇ
A.µÚ¢Ù²½ÖгýÈ¥´ÖÑÎÖеġ¢Ca2+¡¢Mg2+¡¢Fe3+µÈÔÓÖÊ£¬¼ÓÈëµÄҩƷ˳ÐòΪ£º Na2CO3ÈÜÒº¡úBaCl2ÈÜÒº¡úNaOHÈÜÒº¡ú¹ýÂË¡úÊÊÁ¿ÑÎËáµ÷pH
B.MgSO4¡¤7H2OÔÚ¿ÕÆøÖмÓÈÈ¿ÉÖƵÃÎÞË®MgSO4µÄ·½·¨ÓëµÚ¢Ú²½ÏàËÆ¡£
C.´ÓµÚ¢Û²½µ½µÚ¢Ý²½µÄÄ¿µÄÊÇΪÁËŨËõ¸»¼¯Br2
D.Ôڵڢۢܢݲ½ÖÐäåÔªËؾù±»Ñõ»¯
¡¾´ð°¸¡¿C
¡¾½âÎö¡¿
A£®Ñ¡ÏîÖеÄÊÔ¼ÁÌí¼Ó˳ÐòÖУ¬±µÀë×Ó×îºóÎÞ·¨³ýÈ¥£¬Ôò¼ÓÈëµÄҩƷ˳ÐòΪ£ºBaCl2ÈÜÒº¡úNaOHÈÜÒº¡úNa2CO3ÈÜÒº¡ú¹ýÂ˺ó¼ÓÑÎËᣬ¹ÊA´íÎó£»
B£®MgSO4¡¤7H2OÔÚ¿ÕÆøÖмÓÈÈ¿ÉÖƵÃÎÞË®MgSO4£¬¶øµÚ¢ÚÖеÄMgCl26H2OÍÑË®¹ý³ÌÖÐþÀë×ÓÒ×Ë®½âÉú³ÉÇâÑõ»¯Ã¾³Áµí£¬ÔÚÂÈ»¯ÇâÆøÌåÖÐÍÑË®¿ÉÒÔÒÖÖÆþÀë×ÓË®½â£¬Ôò¼ÓÈÈ·½·¨²»Ò»Ñù£¬¹ÊB´íÎó£»
C£®µÚ¢Û²½½«äåÀë×Ó±»Ñõ»¯Îªäåµ¥ÖÊ£¬µÚ¢Ü²½ÖÐäåµ¥Öʱ»»¹ÔΪäåÀë×Ó£¬µÚ¢Ý²½ÖÐäåÀë×Ó±»Ñõ»¯Îªäåµ¥ÖÊ£¬¹ý³ÌµÄÄ¿µÄÊÇŨËõ£¬¹ÊCÕýÈ·£»
D£®µÚ¢Û²½½«äåÀë×Ó±»Ñõ»¯Îªäåµ¥ÖÊ£¬µÚ¢Ü²½ÖÐäåµ¥Öʱ»»¹ÔΪäåÀë×Ó£¬µÚ¢Ý²½ÖÐäåÀë×Ó±»Ñõ»¯Îªäåµ¥ÖÊ£¬¹ÊD´íÎó£»
¹Ê´ð°¸ÎªC¡£
¡¾ÌâÄ¿¡¿ÔÚÒ»¶¨Î¶ÈÏ£¬10mL0.40mol/L H2O2·¢Éú´ß»¯·Ö½â¡£²»Í¬Ê±¿Ì²â¶¨Éú³ÉO2µÄÌå»ý£¨ÒÑÕÛËãΪ±ê×¼×´¿ö£©ÈçÏÂ±í¡£
t/min | 0 | 2 | 4 | 6 | 8 | 10 |
V(O2)/mL | 0.0 | 9.9 | 17.2 | 22.4 | 26.5 | 29.9 |
ÏÂÁÐÐðÊö²»ÕýÈ·µÄÊÇ£¨ÈÜÒºÌå»ý±ä»¯ºöÂÔ²»¼Æ£©
A£®0~6minµÄƽ¾ù·´Ó¦ËÙÂÊ£ºv£¨H2O2£© mol/(L¡¤min)
B£®6~10minµÄƽ¾ù·´Ó¦ËÙÂÊ£ºv£¨H2O2£©£¼mol/(L¡¤min)
C£®·´Ó¦ÖÁ6minʱ£¬c£¨H2O2£©=0.3mol/L
D£®·´Ó¦ÖÁ6minʱ£¬H2O2·Ö½âÁË50%
¡¾ÌâÄ¿¡¿ÓлúÎïA¿ÉÓÉÆÏÌÑÌÇ·¢½ÍµÃµ½£¬Ò²¿É´ÓËáÅ£ÄÌÖÐÌáÈ¡¡£´¿¾»µÄAΪÎÞÉ«Õ³³íÒºÌ壬Ò×ÈÜÓÚË®¡£ÎªÑо¿AµÄ×é³ÉÓë½á¹¹£¬½øÐÐÁËÈçÏÂʵÑ飺
ʵ Ñé ²½ Öè | ½â ÊÍ »ò ʵ Ñé ½á ÂÛ |
£¨1£©³ÆÈ¡A 9.0g£¬ÉýÎÂʹÆäÆû»¯£¬²âÆäÃܶÈÊÇÏàͬÌõ¼þÏÂH2µÄ45±¶¡£ | ÊÔͨ¹ý¼ÆËãÌî¿Õ£º £¨1£©AµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª£º____¡£ |
£¨2£©½«´Ë9.0gAÔÚ×ãÁ¿´¿O2³ä·ÖȼÉÕ£¬²¢Ê¹Æä²úÎïÒÀ´Î»º»ºÍ¨¹ýŨÁòËá¡¢¼îʯ»Ò£¬·¢ÏÖÁ½Õß·Ö±ðÔöÖØ5.4gºÍ13.2g¡£ | £¨2£©AµÄ·Ö×ÓʽΪ£º_______¡£ |
£¨3£©ÁíÈ¡A 9.0g£¬¸ú×ãÁ¿µÄNaHCO3·ÛÄ©·´Ó¦£¬Éú³É2.24LCO2£¨±ê×¼×´¿ö£©£¬ÈôÓë×ãÁ¿½ðÊôÄÆ·´Ó¦ÔòÉú³É2.24LH2£¨±ê×¼×´¿ö£©¡£ | £¨3£©Óýṹ¼òʽ±íʾAÖк¬ÓеĹÙÄÜÍÅ£º___________¡£ |
£¨4£©AµÄºË´Å¹²ÕñÇâÆ×ÈçÏÂͼ£º | £¨4£©AÖк¬ÓÐ________ÖÖÇâÔ×Ó¡£ |
£¨5£©×ÛÉÏËùÊö£¬AµÄ½á¹¹¼òʽ_____________¡£ |