题目内容
如图,□ABCD中,∠C=108°,BE平分∠ABC,则∠AEB= (▲)
A.18° | B.36° | C.72° | D.108° |
B
∵AB∥CD,∴∠ABC+∠C=180°,
把∠C=108°代入,得∠ABC=180°-108°=72°.
又∵BE平分∠ABC,∴∠ABE=12∠ABC=12•72°=36°.故选B.
把∠C=108°代入,得∠ABC=180°-108°=72°.
又∵BE平分∠ABC,∴∠ABE=12∠ABC=12•72°=36°.故选B.
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