题目内容
已知:如图,□ABCD中,点E是AD的中点,延长CE交BA的延长线于点F.
求证:AB=AF.
求证:AB=AF.

证明:∵四边形ABCD是平行四边形,
∴AB∥CD且AB=CD.∴∠F=∠2, ∠1=∠D.
∵E为AD中点,∴AE="ED."
在△AEF和△DEC中

∴△AEF≌△DEC. AF="CD." ∴AB=AF.

∴AB∥CD且AB=CD.∴∠F=∠2, ∠1=∠D.
∵E为AD中点,∴AE="ED."
在△AEF和△DEC中


∴△AEF≌△DEC. AF="CD." ∴AB=AF.

略

练习册系列答案
相关题目