题目内容
如图,在△ABC中,∠A=36°,AB=AC,BD平分∠ABC,则∠DBC=______.


∵在等腰△ABC中,∠A=36°,
∴∠ABC=∠ACB=
(180-36)=72°,
∵BD平分∠B交AC于点D,
∴∠ABD=∠DBC=
∠B=
×72=36°.
故答案为:36°.
∴∠ABC=∠ACB=
1 |
2 |
∵BD平分∠B交AC于点D,
∴∠ABD=∠DBC=
1 |
2 |
1 |
2 |
故答案为:36°.

练习册系列答案
相关题目