题目内容
如图,AB、AC切⊙O于B、C,AO交⊙O于D,过D作⊙O切线分别交AB、AC于E、F,若OB=6,AO=10,则△AEF的周长是( )
A.10 | B.12 | C.14 | D.16 |
D
∵OB=6,AO=10,
∴AB=,
∵AB、AC切⊙O于B、C,AO交⊙O于D,过D作⊙O切线分别交AB、AC于E、F,
∴AB=AC,ED=EB,FD=FC,
∴△AEF的周长=AE+EF+AF=AF+FD+DE+AE=AF+FC+AE+EB=AC+AB=8+8=16.
故选D.
∴AB=,
∵AB、AC切⊙O于B、C,AO交⊙O于D,过D作⊙O切线分别交AB、AC于E、F,
∴AB=AC,ED=EB,FD=FC,
∴△AEF的周长=AE+EF+AF=AF+FD+DE+AE=AF+FC+AE+EB=AC+AB=8+8=16.
故选D.
练习册系列答案
相关题目