题目内容
【题目】如图,中,
,把
绕着
点逆时针旋转,得到
,点
在
上.
(1)若,求得
度数;
(2)若,
,求
中
边上的高.
【答案】(1)∠BAC =50°;(2)
【解析】
解:(1) 由旋转得△ACB≌△DEB
∴BD = BA
∴∠BAD =∠BDA=
∴∠ABD=
∴∠ABC =∠ABD=
∵∠C=
∴∠BAC=·········································································· 5分
(2) ∵BC = 8,AC= 6,∠C=
∴
∵∠DEB =∠C=且BE=BC= 8,DE ="AC" = 6
∴AE =" AB" – BE = 2
在Rt△DEA中,
设AD边上的高为h
∴
∴······················································· 10分
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