题目内容
计算:
(1)(π-2013)0+
+|
-2|;
(2)(4
-4
+3
)÷2
.
(1)(π-2013)0+
12 |
3 |
(2)(4
6 |
|
8 |
2 |
(1)原式=1+2
+2-
=3+
;
(2)原式=4
÷2
-2
÷2
+6
÷2
=2
-1+3
=2
+2.
3 |
3 |
=3+
3 |
(2)原式=4
6 |
2 |
2 |
2 |
2 |
2 |
=2
3 |
=2
3 |
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