题目内容
计算:
(1)3
-2
-4
+3
(2)(
-1)2-(
)-1+
+(1-
)0
(3)
×2
÷
(4)
+a
-b
-
.
(1)3
2 |
12 |
|
48 |
(2)(
3 |
1 |
2 |
4 | ||
|
2 |
(3)
a |
b |
a2b |
|
2 |
3 |
a3b |
(4)
a2b |
|
|
ab2 |
(1)原式=3
-4
-
+12
=2
+8
;
(2)原式=3-2
+1-2+2(
-1)+1=3-2
+1-2+2
-2+1=1;
(3)原式=
•2•
=
=
•
=3;
(4)原式=a
+
-
-b
=a
-b
.
2 |
3 |
2 |
3 |
2 |
3 |
(2)原式=3-2
3 |
3 |
3 |
3 |
(3)原式=
a |
b |
3 |
2 |
a2b•
|
3a |
b |
|
3a |
b |
b |
a |
(4)原式=a
b |
ab |
ab |
a |
b |
a |
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