题目内容
如图,在Rt△ABC中,∠C=90°,AB=10,若以点C为圆心,CB长为半径的圆恰好经过AB的中点D,则AC的长等于( )

A.5
| B.5 | C.5
| D.6 |
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连接CD,在Rt△ABC中,则CD=BC=
=5,依据勾股定理可求
AC=
=
=5
.
故选A.

AB |
2 |
AC=
AB2-BC2 |
102-52 |
3 |
故选A.
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