题目内容
计算:
(1)|-4|-(-2)2+(
)0-2-1
(2)-3x2•2y•(2xy2)3÷(-2xy5)
(1)|-4|-(-2)2+(
2013 |
(2)-3x2•2y•(2xy2)3÷(-2xy5)
(1)原式=4-4+1-
=
.
(2)原式=-3x2•2y•8x3y6÷(-2xy5)
=(3×2×8×
)x2+3-1y1+6-5
=24x4y2.
1 |
2 |
=
1 |
2 |
(2)原式=-3x2•2y•8x3y6÷(-2xy5)
=(3×2×8×
1 |
2 |
=24x4y2.
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