ÌâÄ¿ÄÚÈÝ
³¤ÆÚʹÓõÄË®ºøµ×²¿½áÓÐÒ»²ãË®¹¸£¬ÆäÖ÷Òª³É·ÖÊÇ̼Ëá¸ÆºÍÇâÑõ»¯Ã¾£¬Îª½Ï׼ȷ²â¶¨Ë®¹¸ÖÐÇâÑõ»¯Ã¾µÄº¬Á¿£¬ÊµÑéС×é·Ö±ðÈ¡Èý·ÝͬÑùµÄË®¹¸ÑùÆ·¸÷7.00g£¬ÀûÓÃÈçͼËùʾװÖÃÁ¬Ðø½øÐÐÈý´ÎʵÑ飬²¢½«Ã¿´ÎʵÑéÖÐ×°ÖÃBµÄÖÊÁ¿±ä»¯¼Ç¼ÓÚϱí
| µÚÒ»´Î | µÚ¶þ´Î | µÚÈý´Î | ƽ¾ùÖµ |
B×°ÖÃÔö¼ÓµÄÖÊÁ¿ | 2.17 | 2.22 | 2.21 | |
£¨1£©µÚÒ»´ÎʵÑé²âµÃÊý¾Ý½ÏµÍµÄÔÒòÊÇ___________£»
£¨2£©Æ½¾ùÿ·ÝË®¹¸ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îª___________¿Ë£®
2.20£»5.00£®
½âÎöÊÔÌâ·ÖÎö£ºÆ½¾ùÖµ==2.20g£»
£¨1£©µÚÒ»´ÎʵÑéÉú³ÉµÄ¶þÑõ»¯Ì¼Ã»ÓÐÈ«²¿½øÈëB×°ÖÃÖÐÈ¥£¬ËùÒÔµÚÒ»´ÎʵÑé²âµÃÊý¾Ý½ÏµÍ£»¹ÊÌµÚÒ»´ÎʵÑéÉú³ÉµÄ¶þÑõ»¯Ì¼Ã»ÓÐÈ«²¿½øÈëB×°ÖÃÖÐÈ¥£»
£¨2£©Éèƽ¾ùÿ·ÝË®¹¸ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl¨TCaCl2+CO2¡ü+H2O
100 44
x 2.20g
x=5.00g
´ð£ºÆ½¾ùÿ·ÝË®¹¸ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îª5.0g£®
¿¼µã£ºÓйػ¯Ñ§·½³ÌʽµÄ¼ÆËã
ΪÁ˲ⶨijţÄÌÑùÆ·Öе°°×Öʵĺ¬Á¿£¬ÏÖ²ÉÓ᰸Ƕû´ï·¨¡±·Ö½âÆäÖеĵ°°×ÖÊ¡£ÆäÔÀíÊǰѵ°°×ÖÊÖеĵªÔªËØÍêȫת»¯³É°±Æø(»¯Ñ§Ê½ÎªNH3)£¬ÔÙÓÃÏ¡ÁòËáÎüÊÕ°±Æø£¬·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º2NH3+H2SO4=(NH4)2SO4
ÏÖÈ¡¸ÃÅ£ÄÌÑùÆ·30 mL£¬Ó᰸Ƕû´ï·¨¡±·Ö½âÆäÖеĵ°°×ÖÊ£¬²úÉúµÄ°±ÆøÓÃ9.5 gÈÜÖÊÖÊÁ¿·ÖÊýΪ4.9%µÄÏ¡ÁòËáÇ¡ºÃÍêÈ«ÎüÊÕ¡£¼ÆËã²¢»Ø´ðÏÂÁÐÎÊÌ⣺
(1)²úÉú°±ÆøµÄÖÊÁ¿ÊǶàÉÙ¿Ë£¿(¼ÆËã½á¹û¾«È·µ½0.01 g£¬ÏÂͬ)
(2)30 mLÅ£ÄÌÖꬵªÔªËصÄÖÊÁ¿ÊǶàÉÙ¿Ë£¿
(3)ÏÂͼÊǸÃÅ£ÄÌ°ü×°±êÇ©µÄ²¿·ÖÄÚÈÝ¡£ÒÑ֪ţÄÌÖеĵ°°×Öʺ¬µªÔªËصÄÖÊÁ¿·ÖÊýΪ16%£¬ÇëÄãͨ¹ý¼ÆËãÈ·¶¨£¬¸ÃÅ£ÄÌÑùÆ·Öе°°×Öʵĺ¬Á¿ÊÇ·ñ´ïµ½ÁË°ü×°±êÇ©Ëù±êʾµÄµ°°×ÖʵÄÖÊÁ¿±ê×¼¡£
ÅäÁÏ£ºÏÊÅ£ÄÌ ±£ÖÊÆÚ£º8¸öÔ ¾»º¬Á¿£º250 mL/ºÐ ÓªÑø³É·Ö£º(ÿ100 mL) ¸Æ¡Ý0.11 g Ö¬·¾¡Ý3.30 g µ°°×ÖÊ¡Ý2.90 g |