题目内容
(1-
+
-
+
-
+…+
-
+
)×10的整数部分是______.
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 8 |
| 1 |
| 10 |
| 1 |
| 96 |
| 1 |
| 98 |
| 1 |
| 100 |
设原式=N,则N=5(2-1+
-
+
-…-
+
),
N<5(2-1+
-
+
-
+
-
)=
<7,
(
-
)+(
-
)+…+(
-
)>0,
所以N>5(2-1+
-
+
-
)=
>6,
即7>N>6,
也就是N=6.…,整数部分是6,
答:整数部分为6.
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 49 |
| 1 |
| 50 |
N<5(2-1+
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 7 |
| 83 |
| 12 |
(
| 1 |
| 7 |
| 1 |
| 8 |
| 1 |
| 9 |
| 1 |
| 10 |
| 1 |
| 49 |
| 1 |
| 50 |
所以N>5(2-1+
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 5 |
| 73 |
| 12 |
即7>N>6,
也就是N=6.…,整数部分是6,
答:整数部分为6.
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