题目内容
简便运算
①
×27+27×
②[2.1-2.1×(2.1-2.1)]÷2.1
③
×5+
×2+
×3
④4-
-
.
①
| 3 |
| 8 |
| 5 |
| 8 |
②[2.1-2.1×(2.1-2.1)]÷2.1
③
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
④4-
| 4 |
| 9 |
| 5 |
| 9 |
分析:算式①③可根据乘法分配律计算;
算式②根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
算式④可根据一个数减两个数,等于用这个数减去这两个数的和的减法性质进行计算.
算式②根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
算式④可根据一个数减两个数,等于用这个数减去这两个数的和的减法性质进行计算.
解答:解:①
×27+27×
=(
+
)×27,
=1×27,
=27;
②[2.1-2.1×(2.1-2.1)]÷2.1
=[2.1-2.1×0]÷2.1,
=[2.1-0]÷2.1,
=2.1÷2.1,
=1;
③
×5+
×2+
×3
=(5+2+3)×
,
=10×0.75,
=7.5;
④4-
-
=4-(
+
),
=4-1,
=3.
| 3 |
| 8 |
| 5 |
| 8 |
=(
| 3 |
| 8 |
| 5 |
| 8 |
=1×27,
=27;
②[2.1-2.1×(2.1-2.1)]÷2.1
=[2.1-2.1×0]÷2.1,
=[2.1-0]÷2.1,
=2.1÷2.1,
=1;
③
| 3 |
| 4 |
| 3 |
| 4 |
| 3 |
| 4 |
=(5+2+3)×
| 3 |
| 4 |
=10×0.75,
=7.5;
④4-
| 4 |
| 9 |
| 5 |
| 9 |
=4-(
| 4 |
| 9 |
| 5 |
| 9 |
=4-1,
=3.
点评:完成本题要注意分析式中数据的特点及内在联系,然后运用合适的方法计算.
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