题目内容
9
+99
+999
+
×3.
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| 5 |
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| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
分析:认真观察可知,前三项各自加上
后,都得整数,于是原式变为(9
+
)+(99
+
)+(999
+
),计算即可.
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| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
| 4 |
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| 1 |
| 5 |
| 4 |
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| 1 |
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解答:解:9
+99
+999
+
×3,
=(9
+
)+(99
+
)+(999
+
),
=10+100+1000,
=1110.
| 4 |
| 5 |
| 4 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
=(9
| 4 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
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| 4 |
| 5 |
| 1 |
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=10+100+1000,
=1110.
点评:此题主要考查学生根据数字特点,把
×3分拆给前三项,通过“凑整”,很快得出答案.
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