题目内容
计算.
×27÷
4×
-
×(3-
-
).
| 2 |
| 9 |
| 6 |
| 7 |
4×
| 5 |
| 8 |
| 3 |
| 5 |
| 3 |
| 4 |
| 5 |
| 13 |
| 8 |
| 13 |
分析:(1)把除法改为乘法,约分即可;
(2)先算乘法,再算减法;
(3)括号内的运用减法的性质简算,再算括号外的.
(2)先算乘法,再算减法;
(3)括号内的运用减法的性质简算,再算括号外的.
解答:解:(1)
×27÷
,
=
×27×
,
=7;
(2)4×
-
,
=
-
,
=
;
(3)
×(3-
-
),
=
×[3-(
+
)],
=
×[3-1],
=
×2,
=
.
| 2 |
| 9 |
| 6 |
| 7 |
=
| 2 |
| 9 |
| 7 |
| 6 |
=7;
(2)4×
| 5 |
| 8 |
| 3 |
| 5 |
=
| 5 |
| 2 |
| 3 |
| 5 |
=
| 19 |
| 10 |
(3)
| 3 |
| 4 |
| 5 |
| 13 |
| 8 |
| 13 |
=
| 3 |
| 4 |
| 5 |
| 13 |
| 8 |
| 13 |
=
| 3 |
| 4 |
=
| 3 |
| 4 |
=
| 3 |
| 2 |
点评:此题考查了分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
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