题目内容
计算(要求脱式计算)
(1)3
×(1
÷
)+6×
(2)
÷
÷1
+(
-0.1÷2)×
+1÷1
.
(1)3
| 8 |
| 13 |
| 4 |
| 5 |
| 3 |
| 10 |
| 5 |
| 13 |
(2)
| 5 |
| 7 |
| 2 |
| 3 |
| 1 |
| 14 |
| 1 |
| 4 |
| 5 |
| 13 |
| 1 |
| 12 |
分析:本题根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的;计算过程中可利用乘法分配律计算.
解答:解:(1)3
×(1
÷
)+6×
=
×(
×
)+6×
,
=
×6+6×
,
=(
+
)×6,
=4×6,
=24;
(2)
÷
÷1
+(
-0.1÷2)×
+1÷1
=
×
×
+(0.25-0.05)×
+
,
=1+
×
+
,
=1+
+
,
=2.
| 8 |
| 13 |
| 4 |
| 5 |
| 3 |
| 10 |
| 5 |
| 13 |
=
| 47 |
| 13 |
| 9 |
| 5 |
| 10 |
| 3 |
| 5 |
| 13 |
=
| 47 |
| 13 |
| 5 |
| 13 |
=(
| 47 |
| 13 |
| 5 |
| 13 |
=4×6,
=24;
(2)
| 5 |
| 7 |
| 2 |
| 3 |
| 1 |
| 14 |
| 1 |
| 4 |
| 5 |
| 13 |
| 1 |
| 12 |
=
| 5 |
| 7 |
| 3 |
| 2 |
| 14 |
| 15 |
| 5 |
| 13 |
| 12 |
| 13 |
=1+
| 1 |
| 5 |
| 5 |
| 13 |
| 12 |
| 13 |
=1+
| 1 |
| 13 |
| 12 |
| 13 |
=2.
点评:完成本题要细心注意带分数与假分数,小数与分数之间的互化及通分、约分.
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