题目内容
解方程:
x=
0.75x÷
=3
x-
x=27
14
÷x=
.
| 3 |
| 4 |
| 6 |
| 5 |
0.75x÷
| 1 |
| 3 |
x-
| 2 |
| 5 |
14
| 1 |
| 4 |
| 3 |
| 8 |
分析:(1)根据等式的性质,在方程两边同时除以
求解,
(2)根据等式的性质,在方程两边同时乘以
,再同时除以0.75求解,
(3)先化简,再根据等式的性质,在方程两边同时除以
求解,
(4)根据等式的性质,在方程两边同时乘以x,再同时除以
求解.
| 3 |
| 4 |
(2)根据等式的性质,在方程两边同时乘以
| 1 |
| 3 |
(3)先化简,再根据等式的性质,在方程两边同时除以
| 3 |
| 5 |
(4)根据等式的性质,在方程两边同时乘以x,再同时除以
| 3 |
| 8 |
解答:解:(1)
x=
,
x÷
=
÷
,
x=
;
(2)0.75x÷
=3,
0.75x÷
×
=3×
,
0.75x=1,
0.75x÷0.75=1÷0.75,
x=
;
(3)x-
x=27,
x=27,
x÷
=27÷
,
x=45;
(4)
÷x=
,
÷x×x=
×x,
=
x,
÷
=
x÷
,
x=
.
| 3 |
| 4 |
| 6 |
| 5 |
| 3 |
| 4 |
| 3 |
| 4 |
| 6 |
| 5 |
| 3 |
| 4 |
x=
| 8 |
| 5 |
(2)0.75x÷
| 1 |
| 3 |
0.75x÷
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
0.75x=1,
0.75x÷0.75=1÷0.75,
x=
| 4 |
| 3 |
(3)x-
| 2 |
| 5 |
| 3 |
| 5 |
| 3 |
| 5 |
| 3 |
| 5 |
| 3 |
| 5 |
x=45;
(4)
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 3 |
| 8 |
| 1 |
| 4 |
| 3 |
| 8 |
| 3 |
| 8 |
| 3 |
| 8 |
x=
| 2 |
| 3 |
点评:本题考查了学生根据等式的性质解答方程的能力,注意等号对齐.
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