题目内容

6.脱式计算.
437-391÷23                     $\frac{7}{4}×12.5×\frac{5}{7}×8$            $\frac{7}{16}×40-\frac{5}{16}÷\frac{1}{40}$
80.3-33.3×0.5÷0.37           ($\frac{3}{4}-\frac{2}{3}$)×12÷0.1          $\frac{3}{8}×[\frac{8}{9}÷(\frac{5}{6}+\frac{3}{4})]$.

分析 (1)先算除法,再算减法;
(2)利用乘法交换律与结合律简算;
(3)(5)利用乘法分配律简算;
(4)先算乘法,再算除法,最后算减法;
(6)先算加法,再算除法,最后算乘法.

解答 解:(1)437-391÷23 
=437-17
=420;

(2)$\frac{7}{4}×12.5×\frac{5}{7}×8$     
=$\frac{7}{4}$×$\frac{5}{7}$×12.5×8
=125;

(3)$\frac{7}{16}×40-\frac{5}{16}÷\frac{1}{40}$
=$\frac{7}{16}$×40-$\frac{5}{16}$×40
=($\frac{7}{16}$-$\frac{5}{16}$)×40
=$\frac{1}{8}$×40
=5;

(4)80.3-33.3×0.5÷0.37 
=80.3-16.65÷0.37 
=80.3-45
=35.3;

(5)($\frac{3}{4}-\frac{2}{3}$)×12÷0.1   
=($\frac{3}{4}$×12-$\frac{2}{3}$×12)÷0.1
=1÷0.1
=10;

 (6)$\frac{3}{8}×[\frac{8}{9}÷(\frac{5}{6}+\frac{3}{4})]$
=$\frac{3}{8}$×[$\frac{8}{9}$×$\frac{12}{19}$]
=$\frac{4}{19}$

点评 分数混合运算的关键是搞清运算顺序,正确按运算顺序计算,适当利用运算定律简算即可.

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