题目内容
简算.
×3+
×5+
×10
999×7+111×7
(
+
+
+
)×2002.
| 5 |
| 18 |
| 5 |
| 18 |
| 5 |
| 18 |
999×7+111×7
(
| 1 |
| 2 |
| 1 |
| 7 |
| 1 |
| 11 |
| 1 |
| 13 |
分析:算式(1)运用乘法分配律进行简便计算;
算式(2)运用乘法分配律进行简算;
算式(3)运用乘法分配律进行简算.
算式(2)运用乘法分配律进行简算;
算式(3)运用乘法分配律进行简算.
解答:解:(1)
×3+
×5+
×10,
=
×(3+5+10),
=
×18,
=5;
(2)999×7+111×7,
=(999+111)×7,
=1110×7,
=7770;
(3)(
+
+
+
)×2002,
=
×2002+
×2002+
×2002+
×2002,
=1001+286+182+154,
=1623.
| 5 |
| 18 |
| 5 |
| 18 |
| 5 |
| 18 |
=
| 5 |
| 18 |
=
| 5 |
| 18 |
=5;
(2)999×7+111×7,
=(999+111)×7,
=1110×7,
=7770;
(3)(
| 1 |
| 2 |
| 1 |
| 7 |
| 1 |
| 11 |
| 1 |
| 13 |
=
| 1 |
| 2 |
| 1 |
| 7 |
| 1 |
| 11 |
| 1 |
| 13 |
=1001+286+182+154,
=1623.
点评:此题考查的目的是使学生理解和掌握乘法分配律,并且能够运用乘法分配律进行简便计算.
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