题目内容
1-
-
-
-…-
-
= .
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 512 |
| 1 |
| 1024 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:根据1-
=
,
-
=
,
-
=
,…,可得每个差的分母都是它后面的减数的分母的一半,据此从左向右依次计算即可.
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 8 |
解答:
解:1-
-
-
-…-
-
=
-
-
-…-
-
=
-
-…-
-
=
-…-
-
=
-
=
故答案为:
.
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 512 |
| 1 |
| 1024 |
=
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 512 |
| 1 |
| 1024 |
=
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 512 |
| 1 |
| 1024 |
=
| 1 |
| 8 |
| 1 |
| 512 |
| 1 |
| 1024 |
=
| 1 |
| 512 |
| 1 |
| 1024 |
=
| 1 |
| 1024 |
故答案为:
| 1 |
| 1024 |
点评:此题主要考查了分数的巧算问题,解答此题的关键是判断出:1-
=
,
-
=
,
-
=
,…,每个差的分母都是它后面的减数的分母的一半.
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 8 |
| 1 |
| 8 |
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