题目内容
求未知数X:
x=
x÷
=
x=15
x÷
=
.
| 2 |
| 3 |
| 3 |
| 4 |
x÷
| 2 |
| 3 |
| 8 |
| 9 |
| 5 |
| 8 |
x÷
| 2 |
| 9 |
| 6 |
| 7 |
分析:(1)依据等式的性质,方程两边同时除以
求解,
(2)依据等式的性质,方程两边同时乘
求解,
(3)依据等式的性质,方程两边同时除以
求解,
(4)依据等式的性质,方程两边同时乘
求解.
| 2 |
| 3 |
(2)依据等式的性质,方程两边同时乘
| 2 |
| 3 |
(3)依据等式的性质,方程两边同时除以
| 5 |
| 8 |
(4)依据等式的性质,方程两边同时乘
| 2 |
| 9 |
解答:解:(1)
x=
,
x÷
=
÷
,
x=1
;
(2)x÷
=
,
x÷
×
=
×
,
x=
;
(3)
x=15,
x÷
=15÷
,
x=24;
(4)x÷
=
,
x÷
×
=
×
,
x=
.
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
| 2 |
| 3 |
| 3 |
| 4 |
| 2 |
| 3 |
x=1
| 1 |
| 8 |
(2)x÷
| 2 |
| 3 |
| 8 |
| 9 |
x÷
| 2 |
| 3 |
| 2 |
| 3 |
| 8 |
| 9 |
| 2 |
| 3 |
x=
| 16 |
| 27 |
(3)
| 5 |
| 8 |
| 5 |
| 8 |
| 5 |
| 8 |
| 5 |
| 8 |
x=24;
(4)x÷
| 2 |
| 9 |
| 6 |
| 7 |
x÷
| 2 |
| 9 |
| 2 |
| 9 |
| 6 |
| 7 |
| 2 |
| 9 |
x=
| 4 |
| 21 |
点评:本题主要考查学生依据等式的性质解方程的能力,解方程时注意对齐等号.
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