题目内容
M={x|x2+x-6≤0},N={x||2x+1|>3},则M∩N=( )
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试题答案
B
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M={x|x2+x-6≤0},N={x||2x+1|>3},则M∩N=( )
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| A.(-3,-2]∪[1,2] | B.[-3,-2)∪(1,2] | C.(-3,-2)∪(1,+∞) | D.(-∞,-3)∪(1,2] |
M={x|x2+x-6≤0},N={x||2x+1|>3},则M∩N=( )
A.(-3,-2]∪[1,2]
B.[-3,-2)∪(1,2]
C.(-3,-2)∪(1,+∞)
D.(-∞,-3)∪(1,2]
查看习题详情和答案>>
A.(-3,-2]∪[1,2]
B.[-3,-2)∪(1,2]
C.(-3,-2)∪(1,+∞)
D.(-∞,-3)∪(1,2]
查看习题详情和答案>>
M={x|x2+x-6≤0},N={x||2x+1|>3},则M∩N=
- A.(-3,-2]∪[1,2]
- B.[-3,-2)∪(1,2]
- C.(-3,-2)∪(1,+∞)
- D.(-∞,-3)∪(1,2]