3.参考词汇: tuition n.学费 qualities n.素养

[解题分析]

柱状图是高中英语课本中常见的图形,要求学生通过柱状图图中数据和提示内容写一短文,属于比较、对照类。也可根据提示写为议论文。通常我们采取三段式写法:

第一段:描述图表,得出结论。

第二段:紧扣主题,根据图表比较分析原因,论证结论。

第三段:发表议论,提出自己的看法。

[提炼要点]

分析柱状图数据信息。从图中可看出,黑色代表想上大学,占大多数,约60%;浅黑色代表无所谓,占约30%;白色代表不想上大学,占约10%。

One possible version

Is It The Only Way Out To Go To College?

We had a discussion about whether it is the only way out for senior students to go to college.Views vary from person to person.

The majority of us consider it very necessary to go to college.They think it can widen their knowledge and improve their qualities.Only in this way can they find better jobs after graduation.Very few students, that is about ten percent of the students, think it no use going university, because the tuition is too high for their family to afford.What's more, it's rather hard for college graduates to seek satisfactory jobs.Thirty percent of the students, however, believe “All roads lead to Rome.” Therefore it doesn't make any difference whether they go to college or not.

In my opinion, we can receive a better education at college so that we can serve our motherland.

[语言亮点]

①词汇。如:consider,widen,afford,seek,satisfactory。

②句式。如:形式宾语:The majority of us consider it very necessary to go to college.

倒装:Only in this way can they find better jobs after graduation.

主语从句:it's rather hard for college graduates to seek satisfactory jobs.

谚语:All roads lead to Rome.

③过渡词。如:that is about ten percent of the students,what's more, however, in my opinion。

[技巧点拨]

9、作为盐类水解的背景知识:

(1) (08年广东--17)盐酸、醋酸和碳酸氢钠是生活中常见的物质。下列表述正确的是

A.在NaHCO3溶液中加入与其等物质的量的NaOH,溶液中的阴离子只有CO和OH-

B.NaHCO3溶液中:c(H+)+c(H2CO3)=c(OH-)

C.10 mL0.10 mol·L-1CH3COOH溶液加入等物质的量的NaOH后,溶液中离子的浓度由大到小的顺序是:c(Na+)>c(CH3COO-)>c(OH-)>c(H+)

D.中和体积与pH都相同的HCl溶液和CH3COOH溶液所消耗的NaOH物质的量相同

(2)(06年广东--20)氧化铜有多种用途,如用作玻璃着色剂、油类脱硫剂等。为获得纯净的氧化铜以探究其性质,某同学用工业硫酸铜(含硫酸亚铁等杂质)进行如下实验:

     ⑴制备氧化铜

    工业CuSO4      CuSO4溶液   CuSO4·5H2O  ……  CuO

    ②步骤Ⅱ的目的是除铁。操作是:滴加H2O2溶液,稍加热;当Fe2+转化完全后,慢慢加入Cu2(OH)2CO3粉末,搅拌,以控制溶液pH=3.5;加热煮沸一段时间,过滤,用稀硫酸酸化滤液至pH=1。控制溶液pH=3.5的原因是                        。

(3) (07广东--25)黄铁矿(主要成分为FeS2)是工业制取硫酸的重要原料,其煅烧产物为SO2和Fe3O4。

  (4)将黄铁矿的煅烧产物Fe3O4溶于H2SO4后,加入铁粉,可制备FeSO4。酸溶过程中需保持溶液足够酸性,其原因是                       。

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