摘要:即.容易知道 AB⊥平面PDC.所以AB⊥PD.
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| PB |
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(1)求证:FG∥平面PDC;
(2)求λ的值,使得二面角F-CD-G的平面角的正切值为
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| 3 |
(I)求证:AG∥平面PEC;
(Ⅱ)求三棱锥G-PEC的体积.
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(1)求证:BE∥平面PDC;
(2)求证:AB⊥平面PBD.
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| PF |
| PB |
| CG |
| CE |
| 2 |
| 3 |
| 2 |