摘要:17.在△ABC中.A.B.C所对的边分别为a.b.c.A=.(1+)c=2b. (1)求C, (2)若·=1+.求a.b.c. 解:c=2b.得=+=. 则有==cotC+=+.得cotC=1.即C=. (2)由·=1+.得abcosC=1+,而C=.即得ab=1+.则有解得

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