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若集合A={x|x2+x-6=0},B={x|mx+1=0},且BA,求m的值.
集合A={(x,y)|y=+mx+2},B={(x,y)|x-y+1=0且0≤x≤2},若A∩B≠,求实数m的取值范围.
若集合A={-1,1},B={x|mx=1},且BA,则实数m的值为
A.1
B.-1
C.1或-1
D.1或-1或0
若集合A={-1,1},B={x|mx=1},且A∪B=A,则m的值为
1
-1
1或-1
1或-1或0