摘要:030]解:(1)..····················································· (2)①当的圆心由点向左运动.使点到点并随继续向左运动时. 有.即. 当点在点左侧时.过点作射线.垂足为.则由. 得.则.解得. 由.即.解得. 当与射线有公共点时.的取值范围为.··························· ②当时.过作轴.垂足为.有 ..即. 解得.····································· 当时.有. .解得.·························· 当时.有 . .即. 解得.························································· 当是等腰三角形时..或.或.或.···············
网址:http://m.1010jiajiao.com/timu_id_2579994[举报]
根据下表的对应值
| x | 3.23 | 3.24 | 3.25 | 3.26 |
| ax2+bx+c | -0.06 | -0.02 | 0.03 | 0.09 |
A. 3<x<3.23 B. 3.23<x<3.24
C. 3.24<x<3.25 D. 3.25<x<3.26 查看习题详情和答案>>