摘要:16.如图.O为直线AB上一点..OE是OC的反向延长线.以下两个结论:①∠AOC与∠BOD互为余角,②∠AOC与∠BOE相等.则 A.①②都对 B.①②都错 C.①对②错 D.①错②对
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①E为△ABP的外心;②∠PEB=90°;③PC•BE=OE•PB;④
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