摘要: 解方程: =-2 2. 解不等式: (x+3)-3
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用换元法解方程
+
=11时若设
=y,则可得到整式方程是( )
| 8(x2+2x) |
| x2-1 |
| 3(x2-1) |
| x2+2x |
| x2-1 |
| x2+2x |
| A、3y2-11y+8=0 |
| B、3y2+8y=11 |
| C、8y2-11y+3=0 |
| D、8y2+3y=11 |