摘要:20.化学反应N2+3H2 2NH3的能量变化如图所示.该反应的热化学方程式是( ) A.N2(g)+3H2(g) 2NH3(1),△H=2 kJ/mol B.N2(g)+3H2(g) 2NH3(1),△H=2(b-a) kJ/mol C.N2(g)+H2(g) NH3(1),△H= kJ/mol D.N2(g)+H2(g) NH3(g),△H=(a+b) kJ/mol
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化学反应N2+3H2?2NH3的能量变化如图所示,该反应的热化学方程式是( )

| A、N2(g)+3H2(g)?2NH3(l);△H=2(a-b-c) kJ/mol | ||||
| B、N2(g)+3H2(g)?2NH3(g);△H=2(b-a) kJ/mol | ||||
C、
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D、
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| A、N2(g)+H2(g)→NH3(1)-46 kJ | B、N2(g)+H2(g)→NH3(g)-454 kJ | C、N2(g)+3 H2(g)→2 NH3(g)+92 kJ | D、N2(g)+3 H2(g)→2 NH3(1)+431.3 kJ |