摘要:21. (1)∵A1在平面BCD上的射影O在CD上. ∴A1O⊥平面BCD.又BC⊂平面BCD.∴BC⊥A1O. 又BC⊥CO.CO∩A1O=O.CO⊂平面A1CD.A1O⊂平面A1CD. ∴BC⊥平面A1CD.又A1D⊂平面A1CD.∴BC⊥A1D. (2)∵四边形ABCD为矩形. ∴A1D⊥A1B.由(1)知BC⊥A1D. 又BC∩A1B=B.BC⊂平面A1BC.A1B⊂平面A1BC. ∴A1D⊥平面A1BC.又A1D⊂平面A1BD. ∴平面A1BC⊥平面A1BD. (3)∵A1D⊥平面A1BC.∴A1D⊥A1C. ∵CD=10.A1D=6.∴A1C=8. ∴VA1-BCD=VD-A1BC=××6×8×6=48.

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