摘要:.平行四边形ABCD中.AE平分∠DAB, ∠DAE=20°,则∠C= ,∠B .
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(1)求证:AE⊥DE.
(2)过A、D、E三点作圆交AB于F,连DF交AE于G,若
| AB |
| AE |
| 5 |
| 8 |
| AB |
| a |
| BC |
| b |
(1)用
| a |
| b |
| AE |
| BE |
(2)求作
| BE |
| BA |
| BC |
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| AB |
| AE |
| 5 |
| 8 |
| AB |
| a |
| BC |
| b |
| a |
| b |
| AE |
| BE |
| BE |
| BA |
| BC |