摘要：先化简.后计算:2(a2b+ab2)- [2ab2 -(1-a2b)] -2.其中a= -2.b= 解:2(a2b+ab2)- [2ab2 -(1-a2b)] -2 =2 a2b+2 ab2-[2 ab2 -1 + a2b]-2 =2 a2b+2 ab2-2 ab2 + 1 - a2b-2= a2b-1 ∵a= -2.b= ∴2(a2b+ab2)- [2ab2 -(1-a2b)] -2= a2b-1= (-2)2×-1=2-1=1

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