Question

先化简，后计算：2(a²b+ab²)- [2ab² -(1-a²b)] -2，其中a= -2，b=

Answer 1

        解：2(a²b+ab²)- [2ab² -(1-a²b)] -2 =2 a²b+2 ab²-[2 ab²  -1 + a²b]-2       

           =2 a²b+2 ab²-2 ab² + 1 - a²b-2= a²b-1                                                             

          ∵a= -2，b=

     ∴2(a²b+ab²)- [2ab² -(1-a²b)] -2= a²b-1= (-2)²×-1=2-1=1