摘要:3-, 12-21 .
网址:http://m.1010jiajiao.com/timu3_id_667353[举报]
附加题:(1)下列等式:21=2;22=4;23=8;24=16;25=32….通过观察,用你所发现的规律确定22006的个位数字是 .
(2)计算1+3+32+33+…+399+3100
设S=1+3+32+33+…399+3100则3s=3+32+33+…3100+3101
3S-S=(3+32+33+…+3101)-(1+3+32+33+…+3100)=3101-1
S=
利用上述方法计算1+8+82+…+82007的值. 查看习题详情和答案>>
(2)计算1+3+32+33+…+399+3100
设S=1+3+32+33+…399+3100则3s=3+32+33+…3100+3101
3S-S=(3+32+33+…+3101)-(1+3+32+33+…+3100)=3101-1
S=
| 3101-1 | 2 |
利用上述方法计算1+8+82+…+82007的值. 查看习题详情和答案>>
计算:
(1)(-5)-(+3)+(-9)-(-7)+
;
(2)10-23+32-17-21+45;
(3)(-3
)+(+2
)-(+2
)-(-7
);
(4)-9.2-(7.1)-(-3)+6
+(+2.9);
(5)3.6+41.8-12
-11-51
;
(6)-
-
-
+2
-
-
.
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(1)(-5)-(+3)+(-9)-(-7)+
| 1 |
| 2 |
(2)10-23+32-17-21+45;
(3)(-3
| 5 |
| 6 |
| 2 |
| 5 |
| 1 |
| 6 |
| 3 |
| 5 |
(4)-9.2-(7.1)-(-3)+6
| 1 |
| 5 |
(5)3.6+41.8-12
| 3 |
| 5 |
| 4 |
| 5 |
(6)-
| 1 |
| 8 |
| 2 |
| 5 |
| 4 |
| 9 |
| 3 |
| 8 |
| 3 |
| 5 |
| 5 |
| 9 |
计算下列各题
(1)(-3.2)-(-
)-(+4.8)+
;
(2)(-1.25)×(-
)÷(-
);
(3)32×(-
)+(-11)×(-
)-21×(-
);
(4)-22+8÷(-2)3-2×(
-
).
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(1)(-3.2)-(-
| 3 |
| 4 |
| 1 |
| 4 |
(2)(-1.25)×(-
| 1 |
| 4 |
| 1 |
| 8 |
(3)32×(-
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
(4)-22+8÷(-2)3-2×(
| 1 |
| 8 |
| 1 |
| 2 |