摘要:26. (1)如图1.图2.图3.在中.分别以为边.向外作正三角形.正四边形.正五边形.相交于点. ①如图1.求证:, ②探究:如图1. , 如图2. , 如图3. . (2)如图4.已知:是以为边向外所作正边形的一组邻边,是以为边向外所作正边形的一组邻边.的延长相交于点. ①猜想:如图4. (用含的式子表示), ②根据图4证明你的猜想. (1)①证法一:与均为等边三角形. .························································································ 2分 且··············································· 3分 . 即························································ 4分 .··················································· 5分 证法二:与均为等边三角形. .························································································ 2分 且························································································ 3分 可由绕着点按顺时针方向旋转得到··································· 4分 .··························································································· 5分 ②...········································································ 8分 (2)①········································································································ 10分 ②证法一:依题意.知和都是正边形的内角... .即.····························· 11分 .·························································································· 12分 ..······ 13分 . ········································ 14分 证法二:同上可证 .··························································· 12分 .如图.延长交于. . ································ 13分 ················· 14分 证法三:同上可证 .··························································· 12分 . . ························································ 13分 即········································································ 14分 证法四:同上可证 .··························································· 12分 .如图.连接. .···································· 13分 即······························· 14分 注意:此题还有其它证法.可相应评分.
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如图(1)是夹文件用的铁(塑料)夹子在常态下的侧面示意图.AC,BC表示铁夹的两个面,O点是轴,OD⊥AC于D.已知AD=15mm,DC=24mm,
OD=10mm.已知文件夹是轴对称图形,试利用图(2),求图(1)中A,B两点的距离(:
=26).
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下列定义一种关于正整数n的“F运算”:①当n是奇数时,F=3n+5;②n为偶数时,结果是F=n×
×
×
×…(其中F是奇数),并且运算重复进行.例如:取n=26,如图,若n=50,则第2012次“F运算”的结果是( )

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