ÌâÄ¿ÄÚÈÝ
ÈçͼËùʾ£¬Ë®Æ½·ÅÖõĵ¯»É×ó¶Ë¹Ì¶¨£¬Ð¡Îï¿éP(¿ÉÊÓΪÖʵã)ÖÃÓÚˮƽ×ÀÃæÉϵÄAµã£¬²¢Ó뵯»ÉÓҶ˽Ӵ¥£¬´Ëʱµ¯»É´¦ÓÚÔ³¤¡£ÏÖÓÃˮƽÏò×óµÄÍÆÁ¦½«P»ºÂýµØÍÆÖÁBµã£¬´Ëʱµ¯»ÉµÄµ¯ÐÔÊÆÄÜΪEP=21J¡£³·È¥ÍÆÁ¦ºó£¬PÑØ×ÀÃæ»¬ÉÏÒ»¸öÍ£Ôڹ⻬ˮƽµØÃæÉϵij¤Ä¾°åQÉÏ£¬ÒÑÖªP¡¢QµÄÖÊÁ¿·Ö±ðΪm=2kg¡¢M=4kg£¬A¡¢B¼äµÄ¾àÀëLl=4m£¬A¾à×À×Ó±ßÔµCµÄ¾àÀëL2=2m,PÓë×ÀÃæ¼°PÓëQ¼äµÄ¶¯Ä¦²ÁÒòÊý¶¼Îª¦Ì=0.1£¬gÈ¡10m/s2£¬Çó£º
¢ÙСÎï¿éP»¬ÖÁCµãµÄËÙ¶È£¿
¢ÚҪʹPÔÚ³¤Ä¾°åQÉϲ»»¬³öÈ¥£¬³¤Ä¾°åÖÁÉٶ೤£¿
![]()
½â£º£¨1£©Ð¡Îï¿é´ÓBµãÔ˶¯µ½CµãµÄ¹ý³ÌÖУ¬¸ù¾ÝÄÜÁ¿Êغ㶨ÂÉ
Ep-
ÈôСÎï¿é»¬µ½Ä¾°åÓÒ¶ËʱÓ볤ľ°å¾ßÓй²Í¬ËÙ¶È£¬Ëù¶ÔÓ¦µÄ³¤Ä¾°å¾ßÓÐ×îСµÄ³¤
¶ÈLm£¬¸ù¾Ý¶¯Á¿ÊغãºÍÄÜÁ¿Êغ㶨ÂÉ£º
µÃ£º ![]()
![]()
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
| A¡¢Ð¡Ãº¿éÏÈ×÷ÔȼÓËÙÖ±ÏßÔ˶¯£¬ºó×÷ÔÈËÙÖ±ÏßÔ˶¯ | B¡¢Ð¡Ãº¿éÒ»Ö±×÷ÔȼÓËÙÖ±ÏßÔ˶¯ | C¡¢È«¹ý³ÌÖУ¬Ð¡Ãº¿éÏÈÊܵ½ÏòÓҵϬ¶¯Ä¦²ÁÁ¦£¬ºó²»ÊÜĦ²ÁÁ¦×÷Óà | D¡¢È«¹ý³ÌÖУ¬Ð¡Ãº¿éÏÈÊܵ½ÏòÓҵϬ¶¯Ä¦²ÁÁ¦£¬ºóÊܵ½ÏòÓҵľ²Ä¦²ÁÁ¦×÷Óà |