题目内容

如图所示,在矩形ABCD内对角线BD以上的区域存在有平行于AD向下的匀强电场,对角线BD以下的区域存在有垂直于纸面的匀强磁场(图中未标出),矩形AD边长L,AB边长为L。一个质量为m、电荷+q的带电粒子(不计重力)以初速度v0从A点沿AB方向进入电场,在对角线BD的中点P处进入磁场,并从DC边上的Q点垂直于DC离开磁场,试求:

(1)       电场强度的大小

(2)       带电粒子经过P点时速度的大小和方向

(3)       磁场的磁感应强度的大小和方向

【标准解答】

(1)       带电粒子受电场力作用做类平抛运动,则

L=at2··································································································· ①(1分)

L=v0t···································································································· ②(1分)

Eq=ma········································································································ ③(1分)

得 a=,场强为································································· ④(2分)

(2)在竖直方向上做匀变速运动,Y方向分速度为vy,则有

2 a= vy2   得vy==v0································································ ⑤(2分)

到P点时速度为V==v0························································· ⑥(1分)

速度与水平方向的夹角θ满足 =·········································· ⑦(2分)

得此时速度与水平方向的夹角为θ=arctan············································· ⑧(1分)

(3)BD与水平方向的夹角满足 ··························································· ⑨(1分)

则  有v⊥BD············································································ ⑩(1分)

粒子在磁场中运动轨迹的圆心就在D点,则R=BD=L··················· (1分)

由V=v0,qvB=m········································································· (2分)

得·························································································· (1分)

方向垂直纸面向外·················································································· (1分)

【思维点拔】

    若题中边长未知,求BD与CD间的夹角又变成新题

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