题目内容
如图所示,在矩形ABCD内对角线BD以上的区域存在有平行于AD向下的匀强电场,对角线BD以下的区域存在有垂直于纸面的匀强磁场(图中未标出),矩形AD边长L,AB边长为
L。一个质量为m、电荷+q的带电粒子(不计重力)以初速度v0从A点沿AB方向进入电场,在对角线BD的中点P处进入磁场,并从DC边上的Q点垂直于DC离开磁场,试求:
(1) 电场强度的大小
(2) 带电粒子经过P点时速度的大小和方向
(3) 磁场的磁感应强度的大小和方向
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【标准解答】
(1) 带电粒子受电场力作用做类平抛运动,则
L=
at2··································································································· ①(1分)
L=v0t···································································································· ②(1分)
Eq=ma········································································································ ③(1分)
得 a=
,场强为
································································· ④(2分)
(2)在竖直方向上做匀变速运动,Y方向分速度为vy,则有
2 a
= vy2 得vy=
=
v0································································ ⑤(2分)
到P点时速度为V=
=
v0························································· ⑥(1分)
速度与水平方向的夹角θ满足
=
·········································· ⑦(2分)
得此时速度与水平方向的夹角为θ=arctan
············································· ⑧(1分)
(3)BD与水平方向的夹角满足
··························································· ⑨(1分)
则
有v⊥BD············································································ ⑩(1分)
粒子在磁场中运动轨迹的圆心就在D点,则R=
BD=
L···················
(1分)
由V=
v0,qvB=m
·········································································
(2分)
得
··························································································
(1分)
方向垂直纸面向外··················································································
(1分)
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【思维点拔】
若题中边长未知,求BD与CD间的夹角又变成新题